<p>So, I am self studying calculus, and ran across a problem that i have no idea how to solve.
This is barron's AP calculus, 9th Edition, Chapter 7 : Applications of Integration to Geometry, Problem # 26.</p>
<p>The base of a solid is the region bounded by the parabola x^2 = 8y, and the line y = 4, and each plane section perpendicular to the y axis is an equilateral triangle. The volume of the solid is _____</p>
<p>The book says that the answer is 64 rad(3), but i have no idea how it got there.</p>
<p>I understand that i have to integrate the area * dx then multiply it by 2. But i have no idea how to get the area.</p>
<p>Can any one help me with this?? Thank you! (Please show full work)</p>
<p>Draw a sketch of the parabola and the line y=4. Now try to envision the equilateral triangle at a particular y-value, and you’ll see that the base is 2x and the height is x<em>rad3. Thus the area of each triangle above a certain y-value is x^2</em>rad3. You then need to integrate x^2<em>rad3</em>dy from y=0 to y=4. Since it is given that x^2=8y, you can rewrite this as 8y<em>rad3</em>dy. Integrating, you have 4y^2*rad3 from y=0 to y=4. This gives you 64rad3. If any step isn’t clear, feel free to let me know.</p>
<p>I’m not in calc yet, but I actually understood what was done! U guys split the triangle in 1/2 resulting in a 30-60-90 triangle. The base of this triangle is x, the height x<em>rad(3), and the hypotnuse 2x. Then the base of the 30-60-90 is 1/2 the base of the equilateral triangle, so the entire triangle has base 2x and height x</em>rad(3). Then u did the integration part, which is what I have to look forward to learning next year :)</p>