<p>If x = t^3 and y = t^2 + 4, what is y in terms of x? </p>
<p>I know you don't need the calculator.</p>
<p>solve(x=t^3,x)</p>
<p>t^2+4|x=ans(1)</p>
<p>thanks for helping me get the concept.
But I think this is a more sufficient answer?</p>
<p>solve(x=t^3,t)</p>
<p>t^2+4|t=ans(1) </p>
<p>I get x^(2/3) + 4</p>
<p>But sparknotes says 3 (sqrt x^2) + 4</p>
<p>x^(2/3) is the same thing as the cube root of x^2.</p>