<ol>
<li> If x = t3 and y = t2 + 4, what is y in terms of x?</li>
</ol>
<p>This doesn’t require a graphing calculator. All you need to do is rearrange the equation to isolate t, and then set the two equal to each other.</p>
<p>x = 3t
t = x/3</p>
<p>y = 2t + 4
t = (y-4)/2</p>
<p>(x/3) = (y-4)/2</p>
<p>y = (2x/3) + 4</p>
<p>No problem absolutely requires a graphing calculator, but I want to familiarize myself with the y in terms of x with the calculator in the event that I am ever stuck.</p>
<p>If x = t^3 and y = t^2 + 4, what is y in terms of x? </p>
<p>whoops forgot the exponents.</p>
<p>bumppp…</p>
<p>it’s x^(2/3) + 4</p>
<p>To solve, just find what is equal to in terms of x by taking the cube root of x (thus, x^1/3 = t). then plug it in for t to get (x^1/3)^2 + 4. (x^1/3)(x^1/3) = x^2/3. Your answer is x^2/3 + 4. No calculator is necessary for this problem.</p>
<p>I want to know how to do it with the calculator though</p>