<p>uh flipsta g u mean he might have multiplied by the store A and store B right?</p>
<p>Yea that is probably what he did. Cb tried to be tricky with that extra info, and apparently succeeded.</p>
<p>If (x^2-y^2) = 12 what can x-y equal?
I: 1
II: 2
III:4</p>
<p>A I only
B II only
C I and III only
D II and III only
E I, II, and III</p>
<p>B right?</p>
<p>WAS THIS IN THE EXPERIMENTAL SECTION?</p>
<p>Yes, the answer was B. No, it was not in the experimental section.</p>
<p>For the love of god, can someone tell me that the problem "what is the probability that a posative integer less than OR EQUAL TO ten satisfies the following: 5x-3<=14 or something... i didn't read the *<strong><em>ing OR EQUAL To part, and i know it's the only question i got wrong, and it'll be worth like, 20 pts, which *</em></strong>es me off (i made the EXACT same mistake last april). anyway, if it's experimental, i'll be the happiest kid ever. but i don't think it is... btw, right answer is 1/5 for this one (2/10)</p>
<p>Yea, the answer is 1/5. The "or equal" to doesn't matter.</p>
<p>Reykjavic, can you elaborate as to why the answer is 1/5 or 2/10? Many thanks.</p>
<p>5x+3<14
5x<11
x<11/5</p>
<p>The odds of that, if x is an integer, where x is a number 1-10, is 2/10, or 1/5</p>
<p>do they have the same questions on saturday?</p>
<p>Wait im really confused. What was one of the questions on the expermental Section??</p>
<p>Yea, the answer is 1/5. The "or equal" to doesn't matter.</p>
<p>Obviously 10 doesn't satisfy the equation, but remember that you were looking for the probability. So, in fact, it did matter, because then it's x/10 instead of x/9.</p>
<p>Reykjavic</p>
<p>I don't remember that one. Are you sure it wasnt experimental?</p>
<p>Firstly, I remember that the stated questions was
x^2-y^2=12, given that x and y are positive</p>
<p>I. 1
II. 2
III. 4</p>
<p>A. I
B. II
C. I and III
D. II and III
E. I. II. and III</p>
<p>It was not stated that x and y had to be integers, thus making I. 1 possible.
x = 6.5 and y = 5.5
II. x = 4 and y = 2
III. Given that x and y are positive, it cannot be true
x = 3.5 and y = -.5</p>
<p>But the real problem is that, I. and II. are both valid, but we could only choose<br>
one of them?</p>
<p>The answer above is B. It was discussed in the general thread.</p>
<p>Please read what I said and think about it before you respond.</p>
<p>Right...I believe that it DID have to be intergers..</p>
<p>Alphaneo, it did have to be integers.</p>
<p>Zach, the or equal to DOES NOT MATTER. Think about it. You pick numbers 1-10. Now solve
5x +3<14
5x<11
x<11/5</p>
<p>That's without the or qual to, so your answer is x = 1 or 2, which gives you a probability of 1/5. Now lets look at it if you had the "or equal to".</p>
<p>5x + 3<=14
5x<=11
x<=11/5</p>
<p>The only numbers that x could be are still 1 or 2. The answer is the same, "or equal to" or not. The "or equal to" did not affect the problem.</p>
<p>Now I see why it's 1/5, lol. The original post said the inequality was 5x - 13 <= 14, with a - sign rather than a + one. Many thanks still.</p>