<p>blue book practice test 1 section 3</p>
<h1>11. When the positive integer k is divided by 7, the remainder is 6. What is the remainder when k+2 is divided by 7?</h1>
<p>A.0
B.1
C.2
D.3
E.4</p>
<p>College board's explanation to this one is confusing, can anyone explain how to get "B" better?</p>
<p>ahh wth i figured it out, for some reason whenever i put in “13/7” in a calculator, it shows up as 1.85713… but when i don’t it on paper its 1.6 -_- can anyone explain why this is? i guess for these types of problems i wouldn’t trust calculator too much. Are there other type of problems like this that shouldn’t be solved by calc?</p>
<p>I will try my best to explain.
When K was divided by 7, 6 remained. 6 remained because there isn’t enough to divide into 7 again, since 6 is less than 7.</p>
<p>If however you added 1 to K, then the 6 remainder would then be 7 and therefore 0 would remain. Because K would have divided into 7 perfectly.</p>
<p>Now the question asks what is the remainder when K+2 is divided by 7. Well thats simple. If you add 1 to k and 0 remains, then if you add two 1 will be the remainder.</p>
<p>I hope that was not confusing.</p>
<p>ok thank you! i think ive got those type of questions in check now. One last question…what if “k” is a negative? do you do the same process? but negative?</p>
<p>thanks for the explanation … i was stuck on this too …:)</p>
<p>the fastest way to do this is to know that all sat math questions are universally applied, which means you can directly solve from the given materials.</p>
<p>why dont you just plug a numnber in, such as 13, then you will have the B.</p>