<p>@DancingBear
Do you think it might have been because the the questions this test were different than usual? Because I thought the March this was average, but this one seemed really easy to me.</p>
<p>@LoseYourself</p>
<p>No, the question asked for
f(x) + h(x) = g(x)</p>
<p>@DancinggBear
It was 0, trust me. I intially put 1 because I thought the columns were organized in the same order as the equation, but I realized they weren’t and changed my answer.</p>
<p>Well it’s ok. The curve will be -2 800 /crying in disillusionment.</p>
<p>1024 ,1/32 ,32 ,1 ,32 ,32 ,1024</p>
<p>a+b=70- triangle question, a,b,c
1024 for sequential question
f(2x)=(f(x))^2
1 for MINIMUM distance between points on circle
20 possible entrances/exits to monument
9 max number days
500 Closest integer to surface area of cylinder
None for if x is an even integer, which MUST be odd
1.3 sum of price of 1 soda and 1 pretzel
10 for average of X Y Z
96pi+64 - overlapping circles
36 - question with 86 as median in 101 consecutive numbers
3 - length of BD slope -2/3
90% - x% C(x) question 10x/101-x
5/12 Probability of something greater than 90 for pressure OR both or the other
s for the triangle question r=t and you had to solve for U
isosceles right triangle NOT possible (perimeter 12, integer side lengths)
256 cant remember
0 parallelogram, slopes
t^2-9 one with s^2-81 / s-9 =t^2
5 - 4.8 and 5.1 rounding
-2
y+2, something with y=x+2 or something
36 , lowest possible number in 101 consecutive integers, median 86
0 - columns question with f(x), g(x), h(x)
8 - Arc question how much bigger is this arc than that arc</p>
<p>Grid-ins:</p>
<ol>
<li>4000 -boxes of candy price or pounds</li>
<li>402- random “solve for y” (x+2)/(10) = 40 and (x+y)/(20) = 40</li>
<li>22 - average # of members on wednesday</li>
<li>72 - Area of shaded area, rectangle and semicircle</li>
<li>2.5 y=(k-1)^2 point (3,10)</li>
<li>78 -angle of x in triangle with angle y,y,y</li>
<li>.8 = probability of MISmatching sweater +scarf</li>
<li>9 Solve for K 27^x=ka</li>
<li>.5 .25- -.25=.5 (1 answer to that absolute value of y question)</li>
<li>3600 - n=k^2 n divisible by 24 AND 10</li>
</ol>
<p>yea this sat math was so wierd. I have seen tons of people who said they got 6_ _ in march/may/june w.e. and are saying they got high 700s or 800 yesterday. Personally I got 670 in may and feel like i got 770 yesterday. This may just be correlation and not causation cuz I think if people got 6_ _ last year then they probably studied math a lot, especially on college confidential. Just my 2 cents</p>
<p>so i asked this already but no one answered: for the answer that is a+b=70 was that choice C because all i remember is putting choice C for that one. </p>
<p>And also the arc one was 16 i thought. It asked how many times the arc of one angle was bigger than the arc of the other angle. One angle was 160 degrees and the small on was 20 degrees. and then the radius was 4. but when calculating the smaller angle, the radius had to be half that…2? does this sound right to anyone?</p>
<p>If an angle in a circle is smaller than another angle of the circle the “radius of the angle” for lack of a better name, does not change. In addition, I distinctly remember the radius NOT being given.</p>
<p>Did anyone else have a question about a box, with inside lengths of 12, you had to find out how many balls with a radius of 3 could fit inside it?</p>
<p>Yeah I think you guys are right. I put 8 at first but like always I like over thought it and changed it. AND I REALLY HOPE IT WAS A C, I cannot afford to get anymore wrong on math.</p>
<p>so far i have like -15 on math and -2 on writing…so awk i wish my talents were a little bit more balanced.</p>
<p>For the arc question, it was drawn to scale. You could have made marks (and found out that 8 fit perfectly) to check your answer. 160<em>2=320, 360-320=40, 40/2 (vertical angles) =20. 160/20 = 8. The circumference is proportional to the angle. Therefore, 8</em>20=160. there’s your answer. 8. I hope most people got this!</p>
<p>does anyone remember the question with a parabola that asked you to solve for k??
i think it showed the parabola and a point on the graph (-1,4) and the equation was y=ax^2 + k</p>