DECEMBER 2008 SAT Subject Test: Math Level 2

<p>@ crunkk, 4 x 5 x 6 = 120 which is divisible by 2 3 and 4</p>

<p>vector problem was sqrt of side1^2+side2^2-side1<em>side2</em>cos130 = don't remember the actual numbesr
lol, law of cosines</p>

<p>um. the vector one was something around 6.3 ish
and there WAS a question on sphere vs cone. not sure about vs cube...</p>

<p>28?!
The problem was both radius and volume are equal
so I just equatied the formulas and plugged a number for 'r'.</p>

<p>Oh, hm, maybe I read the problem wrong?</p>

<p>after one year you have 3500*(1.052)^4</p>

<p>With the vectors you have to use a supplementary angle because you line up the vectors.</p>

<p>you guys are probably right. I misread the problem most likely ><!</p>

<p>lolilaughed - yeah that worked, but when i tried three other numbers, it didn't it came out with a .5</p>

<p>that 2,3,4, problem was you had x,y,z and u wanted to guarantee one of them had to be divisible by 4...that is not always the case.</p>

<p>I recall it was a sphere and a cone with equal volumes of 1000 and equal radii and you wanted to find the height of the cone.</p>

<p>yes it was 1000, what did you get adchia?</p>

<p>the radius was 24.8</p>

<p>V=1000</p>

<p>((pi)(r^2)(h))/3 = ((4/3)(r^3)) = 1000</p>

<p>r=6.2
h=24.8</p>

<p>for the vector I got 8.9 but I did it in a rush and didn't think so I might be wrong.
and what did you guys get on the compound interest one?</p>

<p>hmm...anyone remember the deck question? was the answer 5.4 or something .4?</p>

<p>anyone remember the answer to the a(x-b)...?</p>

<p>it looked like this
ImageShack</a> - Image Hosting :: 61611548yg7.png</p>

<p>actually, one of the roots was tangent to the x axis, giving it a multiplicity of two</p>

<p>we just talked about it...a >0, b=c, c not = d, looking at responses</p>

<p>... for the probablitlty question there were two independed events one of p = 1/3 and the other 2/3 the probability of both occuring is (1/3)x(2/3)= 2/9. the question never said anything about one happening and not the other. also order doesnt matter so long as they both happen so you dont need to multiply the probability by 2 so 4/9 is out. i left the xyz plane question didnt even bother. but the question that said x= ..., the max number of zeros is 2 right i mean cuz its quadratic and cuz b and c arnt specified so they could be any real number so im guessing the answer is 2 zeros but it seemed to easy, kinda like a joe bloggs answer.... lol</p>

<p>no!! i got the compound interest one right but erased it at the end lol...since i thought it couldnt be that easy...oh well...</p>

<p>i agree with theman66</p>

<p>and also.. i thought the vector r+s was the vector connecting r's beginning point and s's ending point?</p>

<p>also...that is not the right cpd interest answer.</p>

<p>the formula is P(1+r/k)^kt where r is interest, k is times compounded a yr, t is yrs, p is principle value.</p>

<p>The thickness of paper was 10 ft?</p>

<p>dang 3 wrong :/</p>

<p>and yeah 10 ft</p>