<p>i think i got 10...but whats the original thickness and how many times did you fold it?</p>
<p>Yes I put two zeros too. It said there are two real solutions and the largest power of a polynomial is how many answers there are..real or not. So x^8-x^2 will have 8 solutions..real and unreal. But since since there were two real solutions, as stated in the question, there are two zeros.</p>
<p>double the thickness 12 times...what was the original thickness?</p>
<p>Okay, if anyone feels bad about their Math II performance this morning, I hope I can cheer you up!
I omitted around 15 and probably got just as many wrong!
WOOO 500s!</p>
<p>:(</p>
<p>^ dont worry I think I have 2-4 :/ and 6 omits that's like a7 50 lol</p>
<p>(.03)(2^n) = Thickness, where n is the number of times folded.</p>
<p>n=12 gives 122 I think, which divided by 12 is 10 ft.</p>
<p>So, Adchia, what was the answer to the compound interest question? The number??</p>
<p>theman66 - you did that wrong, it's (1/3)pi<em>r^2</em>h=(4/3)pi*r^2</p>
<p>You left out a pi in the sphere formula - the only difference between the two is that the cone has *h and the sphere is 4x bigger, so h=4</p>
<p>oh dear, was there an answer for 122, not converted into inches?</p>
<p>i got 3685.57 for cpd interest</p>
<p>No the sphere is r^3. so 4R=12 something</p>
<p>damn..
there was an answer for 122 (SAT trap) but it was 10 ft
Can anyone else confirm that 3685 was an answer choice and it was the correct one?</p>
<p>invenianviam: volume of sphere is 4/3pir^3. using the two formulas yields h=24.8140...</p>
<p>and i do in fact remember the .57 part of the cpd interest q.</p>
<p>you convert it to feet; i'm pretty sure 10 ft is the answer also</p>
<p>I meant 24*</p>
<p>lol, oops - pretty sure I got it right though on the test, I was just using the numbers posted on here, haha, I can't remember most of the questions.</p>
<p>So I put 3545 for the compound interest and 8.9 for the vector.
Did I get either right? lol
I doubt it.</p>
<p>Are you sure it was two zeroes, I thought it was only between -2 and -1 since it did not have to have two zeros between the 2nd and 3rd pt (did not pass x axis)</p>
<p>one of the probs had a zero b/t -2 and -1.. another prob had two zeroes with one zero repeating (multiplicity 2 slash tangent to x axis)</p>
<p>that's a different problem, the two zeroes are for the x=x^2+ whatever one and the one zero one between -2 and -1 is right</p>
<p>Oh yea, you could solve that easily with a ti-89</p>