Equation for SAT score/ Vocabulary????

<p>Hi! I was wondering what the equation was for finding out your score in each section was.
I thought it is like this..... 800-10(54-rounded raw score)....this of course being for the Mathematics section. My goal in each section is to get a 750+ so my SAT score is around 2200+ or so. Also, vocabulary is becoming really aggravating and I really want to raise my score with that section. Any books/ prep guides to purchase at my local Barnes and Nobles? Thank you in advance!</p>

<p>It is usually listed after the practice tests in preparation books. There is no equations, the conversion varies on each test.</p>

<p>800 CR - usually 1, maybe 2 wrong
800 Math - almost always every single one correct
800 Writing - perfect mutiple choice with at least a 10 on essay (sometimes you only need a 9) or a 12 essay with 1 or 2 MC wrong</p>

<p>This is what the curves usually are, but you should still look to see after the practice test in the prep book to see the real curve (and usually range of score)</p>

<p>The curve varies per test, depending on difficulty. </p>

<p>Reading: 1 or 2 wrong is usually an 800, 3 wrong (=minus 4 raw score) is generally a 770 or 760. </p>

<p>Math: -1 can be as low as 760, and as high as 800. It’s usually a 770 or 780.</p>

<p>Writing: 1 MC wrong with an 11 or 12 on the essay will be an 800. 1 wrong with a 10 will be a 790. </p>

<p>The best way to see the curve for raw scores other than “-1” is here: <a href=“http://www.erikthered.com/tutor/SAT-Released-Test-Curves.pdf[/url]”>http://www.erikthered.com/tutor/SAT-Released-Test-Curves.pdf&lt;/a&gt;&lt;/p&gt;

<p>In response to your question about which books to buy, I advise the same resources that the community often speaks highly of: </p>

<p>1) The Official “Blue Book” (which I am sure you have already)
2) Direct Hits, Volumes 1 & 2 (you can’t buy it in Barnes & Noble—only online)
3) The SAT Official Online Course, if you are willing to spend $65</p>

<p>There has to be some mathematical formula for it. Curves I’m sure can be decided with the equation in mind.</p>