Feb 2009 ACT Math

<p>you see i believe they were asking for angle opposite one of the legs of the triangle that was made from the intersection of the pentagon and trapezoid...therefore since one angle was 108 and the sum of a triangle is 180...i did 180 - 108 / 2 = 36. </p>

<p>However we need to know whether or not this is correct based on which angle the question was asking for...</p>

<p>can anyone confirm which angle they were asking for?</p>

<p>oh, i see.
do you by chance remember is 70 was A,B,C, or D?</p>

<p>um let me think..i will try to remember</p>

<p>do you agree with the 36 though... ??</p>

<p>i still think it was asking for the 72 degree angle...but maybe someone else will remember for sure. i mightve read it too fast or something</p>

<p>i believe 70 was (C)</p>

<p>can anyone else confirm whether it was 36 or 72......and which angle they were asking for??</p>

<p>I'm pretty sure they were asking for the two angles of the trapezoid, not the triangle.</p>

<p>so was 36 degrees even an answer??</p>

<p>answer choice**</p>

<p>I don't know, but I'm pretty sure 72 was the right answer. Too bad I went through the right reasoning but somehow got 82. >_></p>

<p>definitely the small angles on the trapezoid, not the isosceles angles. and the answer was 72</p>

<p>i got 72 as well for the pentagon problem</p>

<p>based on this thread, i've gotten all of the math ones right so far!
:D</p>

<p>Could have simply guessed guys..</p>

<p>Trapezoid is 540.</p>

<p>Trianble is 180.</p>

<p>Subtracted= 360</p>

<p>360/4 < somewhere near 80 BUT NOT MORE.</p>

<p>The only one was 72.</p>

<p>was 36 an answer choice??</p>

<p>..i think i may have solved for the angle of the isosceles triangle, but maybe not</p>

<p>if 36 was not an answer choice then i deff didnt do that and got 72..i just cant remember which i solved for</p>

<p>36 was an answer choice. The choices were 36, 72, 82, and I think 108.</p>