<p>i never understood this kind of math problem:</p>
<p>like 3 macroons are to 7 zeplins.</p>
<p>1 zelpin/2 junes</p>
<p>2 junes/5 apples</p>
<p>that wasnt the exact problem but it asked what is the fraction of macroon to apple</p>
<p>Did it say intersecting? I dont think it did, but I might have just been stupid.</p>
<p>omg so easy. ok the first ratio of (im making up things) zoobas to holimatchs was 2:1. holimatchs to merolins was 2:1. so zoobas to merolins was 4:1 (because when there are 2 holimatchs, there are 4 zoobas). merolins to laurens was 2:1, so if there are 2 merolins, there are 4 holimatchs and 8 zoobas. so zoobas to laurens is 8:1</p>
<p>to mrs ferguson:</p>
<p>mrs ferguson, 2 planes that are orthogonal to each other intersect at a point. the question didnt say whether the planes were orthogonal or not, so when 2 planes are perpendicular, they intersect at a point</p>
<p>Yes I guessed and put a point and a line!!! I hope you are right though! lol</p>
<p>That ratio problem was tough but all I did was plug n chug. I picked a number, then figured out how many would equal the last thing then I divided the 2 numbers to figure out the ratio. Most problems I plug n chug lol</p>
<p>Laurastar -
Planes are infinite. They're not rectangles that can be orthogonal to each other at a point. They either intersect at a line or not at all. Mrs. Ferguson is right. </p>
<p>Evilasiandictator-
The Cartesian Plane is like a third plane, so it looks like there's only a point in the intersection of the two planes (x and y axes). The third plane is basically a cross-section, so what you don't see is that although the intersection between the x and y axes looks like a point, it extends infinitely backwards (into the paper its on) and infinitely forwards (towards you). The origin is the intersection between the plane parallel to the piece of paper the coordinate system is drawn on, the x-axis plane and the y-axis plane. That's a really long explanation, but like I'm having a hard trouble explaining what it really looks like.</p>
<p>this will be the last time anyone ever mentions this. Planes meet at a line, not a point. I don't think anyone knows what a plane is. Is it that hard of a question? How can planes meet at a point. It is not possible. The correct answer is a line and no points. Please do not try to argue because you are wrong.</p>
<p>ya seriously, just everyone shut up about the plane problem, whoever ur teachers are, they don't deserve a degree if they say that planes intersect at a point. The answer was line or nothing, period.</p>
<p>r there any other questions people had. Maybe the science, reading or writing sections.</p>
<p>What was the answer to the zeplins and macroons question?</p>
<p>what was that question again?</p>
<p>It was all fractions. 1 macroon = 4 zeplins which equals 2 of something... I dont remember the exact question but it was something like that.</p>
<p>i think i got 16. I'm pretty sure that was my answer. I know that I aced the math question so anyone can ask away any math question. I always get a 36 on it.</p>
<p>always? how many times do u take it!?!</p>
<p>i've taken it 3 times. Its not that hard. For some people it is, but for me, its a joke. I can do those problems in my sleep. Its only because i love math and do a lot of problems.</p>
<p>well can you correctly explain how to do the circle problem, because ive been hearing too many solutions....</p>
<p>please don't bring up the plane anybody...</p>
<p>For the circle one you just use the equation of a circle.
r^2 = (x-h)^2 + (y-k)^2
where (h,k) = the center of the circle</p>
<p>I think in the original problem the radius was seven and it was shifted down 2 units? So...
New center would be (0, -2)
7^2 = (0-0)^2 + (y-o)^2
49 = y^2
y = +/- 7</p>
<p>Is this correct numberone?</p>
<p>Here is what I did for the circle problem. I hope i am doing the correct problem. Tell me if I am doing the wrong problem. They wanted you to find the x intercepts of the circle that was shifted down 2 on the y axis and had a radius of 7. The equation for this circle is x^2 + (y+2)^2 = 49. You expand it and get x^2 + y^2 +4y + 4 = 49. Then, you can substitute y=0 because the x intercept is when y=0. Then you get x^2 + 4 = 49. And x=+ and - 3 sqaure root of 5. Did I make any mistakes? I might have made a mistake somewhere. I am kind of tired now. But I know i did it correctly because I checked it on my calculator.</p>
<p>numberone, what is the curve like on the tests? Can you get a 36 with 1-2 wrong like the SAT, or is it harsher?</p>