Help on Cal integration.

<p>Well, I am currently in Calculus BC and we are doing some reviews.
My teacher gave me a work on integrals, she called it "Integrals of Different Types of 'Maturity'"</p>

<p>Coming to the last problem, I got stucked on a problem involving log.
It looks like this,</p>

<pre><code> 2^log2 (7a) da
</code></pre>

<p>Just to let you know the 2 behind the log is a subscribe. Log2(7a), the whole thing is the power. </p>

<p>Can anybody help me on this one? Much thanks.</p>

<p>Link</a> to Solution.</p>

<p>wow, I learn something new everyday!
.-/--/.-/--../../-./--.</p>

<p>if u cant do that, u shouldnt take the BC test in may</p>

<p>y not, well I dont know how to solve that! Just because I didn't the properties of logarithm, doesn't mean I will do bad in BC exam >_<
--././-/-/../-./--.//---/-.//--/-.--//-././.-./...-/./...</p>

<p>Wait why is 2^log(2)(^7a)=7a. What kind of logarithm property is that???</p>

<p>I just figured it out too.
2^(log[2,7x]) = 7x</p>

<p>Yeah, that seems way too simple.</p>

<p>A</a> Explanation</p>

<p>It's just simple like that, basically, it's just the same as e^ln(7x) = 7x
^_^</p>

<p>Special thanks to Hazhulkhen for helping me on this one. I didn't know about that property or logic. :) </p>

<p>As for the AP exam, I am not going to take Calculus BC. I originally planned to take both. But this year, AB and BC exam are offered at the same day and same time in my schoo. That means I can only choose one of them. I am more inclined toward taking AB. Don't worry, I will be ready when the time comes.</p>

<p>well, I think that if you're taking calc BC then you have to take BC exam though. I don't know what about your school, but in my school, calculus AB is the first half of the book/ year, and calculus BC is the whole book/ year. So it's nonsense to take both exams. Anyway, it's just about college credit transfering, so it's not really important <to me="">
-.../-.-.//.-./---/-.-./-.-/...</to></p>