<p>OK, since SharingGift is crunching numbers and coming up with all these great analytical observations, thought I’d share some of my own calculations.</p>
<p>How many available spots in a boarding school are you really chasing? Let’s take Choate as an example. </p>
<p>Choate total enrollment is approx 860 students, so as an applicant for the Third Form (9th grade) you think, “Great! I’m applying for one in 215 spots” (i.e. 860 ÷ 4).</p>
<p>Wrong!<br>
In each admissions cycle, Choate adds new students to each grade, so the Third Form class is the smallest—only about 160 students.<br>
So you think, “Great! I’m applying for one in 160 spots”</p>
<p>Wrong!<br>
Half the spots are allocated to Boys and half are allocated to Girls.<br>
So you think, “Great! I’m applying for one in 80 spots”</p>
<p>Wrong!<br>
Day students spots are reserved for day students. Boarding spots are reserved for boarders. Int’l spots are reserved for int’ls. Assuming all int’l students will board, the breakdown at Choate for these groups is:
25% Day
15% Int’l
60% Boarding Domestic
100% sum</p>
<p>If you apply these percentages to the 80 boys and 80 girls in the 9th grade, you get:
80<em>25% = 20 Day spots (9th grade boy)
80</em> 15% = 12 Int’l spots (9th grade boy)
80* 60% = 48 Boarding Domestic spots (9th grade boy)</p>
<p>All schools anticipate that some of the applicants they accept will choose to go elsewhere. So the percentage that actually matriculates is called the YIELD. You can get a fairly good empirical guestimate of the school’s yield by this formula:
*Yield = 0.06(SSAT avg ÷ admit rate) + 0.35 **</p>
<p>So for Choate:
0.06 * (85% ÷ 19%) + 0.35 = 0.62 Yield</p>
<p>Now you divide the available slots by the Yield Rate to calculate the number of acceptance letters:</p>
<p>20 spots ÷ 0.62 = 32 Day acceptance letters (9th grade boy)
12 spots ÷ 0.62 = 19 Int’l acceptance letters (9th grade boy)
48 spots ÷ 0.62 = 77 Boarding Domestic acceptance letters (9th grade boy)</p>
<p>If you are an applicant for the Fourth Form (10th grade), there will be approx 60 new 10th graders added (30 boys + 30 girls)-- I am including 5% attrition from the original 9th grade class. </p>
<p>So if you run through the whole analysis, you get:</p>
<p>8 spots ÷ 0.62 = 12 Day acceptance letters (10th grade boy)
5 spots ÷ 0.62 = 7 Int’l acceptance letters (10th grade boy)
18 spots ÷ 0.62 = 29 Boarding Domestic acceptance letters (10th grade boy)</p>
<p>I'm assuming the yield rate is the same for these different categories. Most probably, it's not. Bottom line is that you are chasing much, much fewer than 215 spots.</p>