<p>Okay, so spring break has gotten me off track a bit, and we haven't done this since last quarter, so I pretty much brain dumped right triangles and trig ratios. Can you please assist me on how to solve this? lol. Can you do # 1? And when would I use Cos vs using Sin? </p>
<p>**The link won't work. Well it's a right triangle, with the hypotenuse as 31, long leg as 28, and no short leg. Across the short leg is the angle that needs to be solved. According to the answer sheet, it's 25 degrees. But how?</p>
<p>Cos is Adjacent over Hypotenuse. Sin is Opposite over Hypotenuse.</p>
<p>Use this: SO (Sin= Opposite/Hypotenuse)
H
CA (Cos= Adjacent/Hypotenuse)
H
TO (Tan=Opposite/Adjacent)
A</p>
<p>^The acronym Sohcatoa.</p>
<p>Ok, to find the angle of a right triangle, you need to do an inverse proportion. The formula for your problem would be:</p>
<p>cosX= 28/31</p>
<p>So then you’d need to enter it into your calculator as cos(exponent)-1= 28/31</p>
<p>Does that make any sense? lol.</p>
<p>yeah, I figured it out. lol. Thanks btw.</p>
<p>You’re welcome! That’s probably my longest post. :)</p>