<p>I go to a community college with a total of 37 credits. My transcripts contain a total of 15 classes attempted, 3 C's, and the rest of them are B's, never failed or withdrew from a class. I'm taking intro to healthcare for summer B, and things are looking up with that class because so far I have an A, I'm not sure how much that would raise my GPA. I'm also taking 13 credit hours this fall. How many full-time semesters with all A's will it take to get it up to a 3.5? I'm confident I can get all A's because community college is stupid easy, I just needed to quit smoking weed every morning. So I guess you can say I cleaned up my act...</p>
<p>37<em>2.8+x</em>4=(37+x)*3.5; solve for x</p>
<p>x stands for the amount of credits I would need to get it up to a 3.5?</p>
<p>I went from a 2.7 to a 3.7 in two semesters when I was in community college, but I had to retake one of the classes I had done poorly on to do it. Is that an option for you? After that the lowest grade I ever got was one B- and I was in pretty good shape for transferring.</p>
<p>Go here
[Cumulative</a> GPA Calculator](<a href=“http://science.kennesaw.edu/biophys/bigGPA.html]Cumulative”>http://science.kennesaw.edu/biophys/bigGPA.html)</p>
<p>balls - yes</p>
<p>You need a total of X credits where 0.417X = 37; X ~= 89 credits
You have 37 credits, so you’ll need about 52 more straight A credits to raise your GPA to a 3.5.</p>
<p>Van’s formula will always work as well. However, since you are assuming you’ll get straight A’s, there is an easier formula (if you want to check multiple GPA goals quickly):</p>
<p>Take the rise you want in your GPA (If you want a 3.7, then you want a 0.9 rise). Divide it by (4.0 - your GPA), which equals 1.2 for you. This is the fraction of your total credits that need to be A’s. Take this fraction (X) divide it by (1-X), and multiply it by the number of credits you have taken (37).</p>
<p>EX: If you want a 3.7:
3.7 - 2.8 = 0.9; 0.9/1.2 = 0.75; 0.75/(1-0.75) = 3; 3 * 37 = 111. You’d need 111 more straight A credits to get a 3.7. This is pretty much your upper limit.</p>