Interesting geometry problem... help please

<p>here's the question... Upload</a> Screenshot</p>

<p>..and another one <a href="http://ScrnSht.com/splbzt%5B/url%5D"&gt;http://ScrnSht.com/splbzt&lt;/a&gt;&lt;/p>

<p>I believe the answer for the one with 5 circles is r=2.41, if anyone cares to confirm that.
Didn’t try the other one, but I think it’s fairly simple.</p>

<p>I would really appreciate it if you could go over the steps… :)</p>

<p>Okay I got the 1st one now…</p>

<p>But what about the second problem? I still need help with that one- [Upload</a> Screenshot](<a href=“http://ScrnSht.com/splbzt]Upload”>http://ScrnSht.com/splbzt)</p>

<p>I’m not totally sure about that one, turned out harder than I thought, but I think you find a side of the square, then the diagonal, which is the diameter of the circle, and also the diagonal of the rectangle, and use the Pyth. theorem to find l^2 + w^2 = 10 and then solve that and lw=4 (area) and you get 2 values for each I believe. </p>

<p>There’s no way something like the second questions would come on the SAT though, too many steps and too complex. I doubt even the first one would be in there.</p>

<p>The square will have side sqrt(5), and diagonal sqrt(10). This diagonal is also the diameter of the circle.</p>

<p>In your figure, draw a rectangle so that the above diagonal is also the diagonal of the rectangle (extra credit for math jocks: prove that you can always draw this rectangle). At this point you should be able to come up with two equations for the length and width of the rectangle, jimmy’s are correct.</p>

<p>I ended up with length = sqrt(2), width = 2 sqrt(2) … or reversed.</p>