<p>ugh lame T_T I changed it from 60 to 65 last minute…</p>
<p>what was the answer to the tangent lines one?</p>
<p>mtb- 40</p>
<p>lol guys with the angles given on the triangle I’m pritty sure 65 was right</p>
<p>can someone clarify this with confidence. in this diagram
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are there pairs of identical triangles or not. i am speaking of the 6 small triangles are there 3 pairs of IDENTICAL TRIANGLES???</p>
<p>heres my attempt, I’m getting very weird stuff.</p>
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<p>it is clearly 65. just think of the right side as a separate triangle in order to get 80 (i think). from there solve the triangle with the variable</p>
<p>actually I mislabeled that diagram q should be 100 not 95, so yes the answer is 65, there is no other way</p>
<p>It is clearly 65.</p>
<p>Triangle with the degree we’re looking for: 70 degrees overall. 35 split, the 35 is used for the degree we want to get.</p>
<p>The half triangle (right triangle, half-sized) has a 30 degree at top (from the 60 degree split), the 70 degree that we already know, which means one missing angle would be 80.</p>
<p>Going back to the triangle where we want to find X, we know there’s an 80 degrees, the 35 degrees… 180 - 80 - 35 = 65, the answer.</p>
<p>On the parallel lines/supplementary angle question was there 2 or 1 answer?</p>
<p>by the way, did anyone have the answer pi to the one with the arc?</p>
<p>unfortunately for me, i do agree it is 65 WITHOUT A DOUBT.</p>
<p>wat did everyone get for the problem where there were two shapes and it asked for the area of the shaded region. on both shapes they gave you a bunch of x’s and one number. I dont remember the problem exactly, though. does anyone remember?</p>
<p>12 for the area</p>
<p>^ Yeah, everyone has definitely conceded to the 65º angle one. eg2333 I don’t think I ever answered just “pi” but which question are you referring to?</p>
<p>eg2333, do you remember what that area problem looked like exactly?</p>
<p>there was an arc, ACE I think which covered 180 degree, there were two arcs that covered 45 degrees, and one middle arc that covered 90 degrees. And it asked you to find the length of one the arcs with the 45 degrees. The length of arc ACE was 4pi</p>
<p>I aced it. 'nuff said</p>
<p>I agree w/ 65 as well. Thanks to all those who helped out!</p>
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<p>here is the exact square area problem for joe</p>
<p>Which one was the experimental? </p>
<p>I had two grid-ins (2 and 6.) </p>
<p>And I had two consecutive math sections (5 and 6.)</p>