<p>^Mid 700s. It’s hard to say but since this was a relatively “easy” test, 740?</p>
<p>really i got 6 for reflecting it across the y axis because it had a radius of two and was centered at x=3 y=somehting not important.
what was the answer?</p>
<p>i didnt notice 6 as a answer chocie (i guess i lucked out there) :)</p>
<p>how lucky; goes to show you how a high stress test like the sat can make you fail at some “easy” things lol. I was having a really hard time with one math question during the test because i was dividing x by y instead of y by x and stuff like that… oh well i still hope i did well. good luck to you too.</p>
<p>On the very last one of the test, there was the F(-3)=F(x) one. I distinctly remember f(0) having the same value as f(-3), but everyone is saying that its 2?</p>
<p>no f(2) had the same value as f(-3)</p>
<p>I know I’m pretty late, but I can definitely assure anyone here that the answer was 65 for that particular question.</p>
<p>Why am I so confident? I’ve been solving it for like 5 minutes and I got a sudden epiphany. Suddenly it was like the trumpets playing and the lights of heaven shining on that question.</p>
<p>Then it got shut down on the next question ._.</p>
<p>
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<p>I reflected it over the Y and got an answer.</p>
<p>SHOOT. >_< It wasn’t 6?</p>
<p>Does anyone remember the problems for the grid-ins besides the ones we have exhausted for 5 pages (lol). Like what were some of the ones on the last page?</p>
<p>Umm was the sequence question that asked for the first term over 100 a grid-in question?!?</p>
<p>oh yeah the 158 one</p>
<p>urg. The very last question very well may have taken away an 800</p>
<p>I think the reflection over the x axis was 10</p>
<p>can someone tell me the exact 9or close to exact) wording of the graph f(x)=f(-3) question?? I was pretty sure all we had to do was go to -3 and find the y value.</p>
<p>guys i remember specifically for the triangle one, the bottom left C angle was 60 degrees.
i copied the problem exactly onto the back of my calculator to solve later cos my proctor was a moron.
which makes x 60 degrees</p>
<p>I thought we had all agreed it was 65…</p>
<p>Seriously, does anyone not remember the one with the arc? It was a circle and it was split in to two halves. One of the halves was split into two smaller sections with 45 degree angle and one bigger section with a 90 degree angle. It gave you the total arc length as 4pi and it wanted you to find one of the smaller ones. Or maybe this was just experimental?</p>
<p>sorry i joined in on this late.
as i said before, i copied the exact triangle on the back of my calculator to solve later and im staring at it right now.
the bottom left corning is 60 degrees, divided into 30 and 30.
the top is 25 and 25, bottom right is 35 and 35.
x is 60</p>
<p>im sure theres no way i copied it wrong</p>
<p>I got 65, and I solved that problem in no more than a minute. I remember reading the question, and as I was reading which line bisected what angle, I was already writing down the measures of each individual angle. All of my friends got 65 on it, I am almost positive.</p>
<p>@eg I think that was exp</p>