<p>I put awed because I remember him being more amazed but I’m sure it can go either way</p>
<p>@mizejonathan17 Are they really different questions?!?! :'D that would make me so happy! Can anybody verify this?!?!</p>
<p>For the patti one I remember putting the first girls name. … I think it was patti</p>
<p>@Jellybae ohh man!!! ohh well.</p>
<p>@marrissa It was Patti because I remember thinking “Oh course the lady with the old lady name is the shortest”</p>
<p>@Christen876 I cannot say within 100% certainty, of course, but I’m pretty darn sure they were different questions. I’m nearly positive I put those same answers for two different questions, respectively </p>
<p>@mizejohnathan17 I did too, but I can’t seem to match the question with the answer choice. That’s why I was worried lol!</p>
<p>@Jellybae Wrong, but close
@mizejonathan17 Wrong
@Jarjarbinks23 No, I made it
@Christen876 Lol</p>
<p>It’s a reletively hard problem… hah</p>
<p>Btw, are there any AIME or USAMO qualifiers here?</p>
<p>Another fun probability problem I made to try:</p>
<p>There are 10000 people in a row arranged randomly. Find the probability that the 2014th person is taller than the first person but smaller than the last person. (There are no two people with same height).</p>
<p>Yeah… The Australian Indigenous Mentoring Experience right? </p>
<p>MY FINAL ANSWER IS 1/12 (Which is probably wrong lol)</p>
<p>@personasa</p>
<p>Roughly 8%? @Personasa
*Disclaimer- I’m just a dilettante </p>
<p>I’m going to bed. Hope you guys get your scores you wanted. See you in the morning</p>
<p>@mizejonathan17 do you have any other esoterica you’d like to apportion to all us CCers?</p>
<p>@Personasa it ends up being just 1/6. the binomial distribution adds up to 1, and since you’re end up multiplying everything by 1/6, it’s just 1/6 lol. </p>
<p>@personasa it’s 1/12 or 1/16 (maybe…) either way I can’t do this problem anymore lol</p>
<p>Also @Personasa I’m a 4-time AIME qualifier…sadly not USAMO though. I’ve been pretty effing close. Senior Year will be the year. </p>
<p>And to "
There are 10000 people in a row arranged randomly. Find the probability that the 2014th person is taller than the first person but smaller than the last person. (There are no two people with same height)."</p>
<p>My initial guess is 1/4 : There is an equal chance of being shorter/taller than the first and last person.</p>
<p>@Jarjarbinks23 Well, I might as well share my extrapolations on the postulation of mandated abacination of all bellicose politicians who advocate biannual gabelle installation.</p>
<p>11:11 I wish for good scores lol</p>
<p>dangit it turned 11:12 when I submitted…</p>