<p>Wynter is correct; 1.5 to 0.75 L and 200K to 100K. Both were halved so you’d get 8 L - no change.</p>
<p>What would a -3 and 1 blank be? I feel like I’m on the edge of an 800…scared!</p>
<p>Wynter is correct; 1.5 to 0.75 L and 200K to 100K. Both were halved so you’d get 8 L - no change.</p>
<p>What would a -3 and 1 blank be? I feel like I’m on the edge of an 800…scared!</p>
<p>The reason there’s no change is because volume and pressure are indirectly related. So with a halved pressure, volume was supposed to go up 2x… but since it shrinked as well, then it stayed the same.</p>
<p>@Wynter: thanks, I probably got it wrong because I honest to goodness don’t remember what I put but there is an itchy feeling that I plugged in (.75/1.5) instead and got 2L (which I now know is incorrect)</p>
<p>For the Function of Temp:
I got C as well. I guessed haha.</p>
<p>And on the compiled list of stuff, I see…
2p group: 3 UNPAIRED ELECTRONS
I think I put 6 haha. How come it’s 3?</p>
<p>There are only three orbitals, so the fourth, fifth, and sixth electrons pair up with the first three.</p>
<p>I… see kind of. I just imagined it as 3 orbitals with 2 electrons in each one. XD</p>
<p>That’s right, but then each orbital has a pair of electrons with opposite spins. So you can have a maximum of 3 unpaired electrons (1 per orbital) by themselves before they start becoming paired up.</p>
<p>wasn’t there another question about density vs. temp? something about water being diff density at 4 deg, than at 0 deg? Darn, i think i got it wrong.</p>
<p>I sure hope the first one said “under constant volume” :</p>
<p>The one about the gas did say it was in a container at constant volume and did ask which answer choice was not dependent on temperature. There was an answer choice about water being denser at 4 degrees Celsius than 0 degrees Celsius, but that wasn’t the correct answer for that question. I don’t remember the full question though, sorry.</p>
<p>I remember choosing the temp difference because water is more dense than ice. Don’t remember the question that sparked my reasoning though.</p>
<p>Anyone remember the question for that one? I know that water’s denser than ice but I don’t remember that question.
Edit: there was a question strictly on water … maybe that was it. The answer was that it’s not a strong electrolyte.</p>
<p>Density counts since the Ideal Law says that PV=nRT.</p>
<p>Thus P=(n/V)RT=(density/molar mass)RT.</p>
<p>Also, deviations from ideal behavior are (P+an^2/v^2)(V-nb)=RT. The deviations themselves are dictated by a and b, NOT T. The answer is B</p>
<p>Wasn’t it related to water being denser at 4 degrees Celcius than at 0 degrees Celcius? (Which it is)</p>
<p>I think the answer to that was “Water is a strong electrolyte”^</p>
<p>Hey guys, for the Relationship Analysis section, there’s an organic chem question about isomerism. My answer, which I now believe may be wrong, is T T CE. </p>
<p>Statement 1 was something and something are isomers (True)
Statement 2 was because … has different molecular structure.</p>
<p>I clearly recall I was stumped on that question because I couldn’t decide if Statement 2 was true, since isomers differ in structural formula but wasn’t sure if the term “molecular structure” can be used interchangably in this context. If “molecular structure” doesn’t fit, then I believe it would be a T F. </p>
<p>But… any opinions?</p>
<p>WRT to the water question (they asked for false statements right?), my answer was also water is a strong electrolyte. </p>
<p>Was torn between that answer and “water is a weak acid”. Yes for False - water is a weak acid: water has a neutral pH. No for False - water is a weak acid: Based on Brosted-Lowry, it can still give up protons. It’s also amphoteric.</p>
<p>Water is not weak acid…</p>
<p>N2
was it covalent or london dispersion?</p>
<p>@rorror45
the N2 question was London Dispersion.</p>
<p>Lol, maybe I just remembered one of the choices…hopefully I chose the right one. </p>
<p>Water is a weak acid. Pure water reacts with itself to become hydronium and hydroxide and then the reverse reaction occurs.</p>