<p>@Daisie
i think so, because volume was constant.
@harharparis
i hope so! (:</p>
<p>wait, no i think its heat of sublimation…
but i’ve never heard of heat of sub, so i guessed. :
also, are you sure you dont do grad cylinder + bunsen?
answer choice A was weird too…
i put grad cylinder + bunsen…
but you dont flush a buret with titrant, or else it’ll neutralize, no?</p>
<p>The CO2 involving the polar bonds was TT.
Linear shape does not always equate to a polar molecule. Take HCl for instance.
So it is not CE.</p>
<p>So were there 2 sublimations in a row in that one? Also a neutralization and a reduction?</p>
<p>Sublimation for iodine gas. I put heat of sublimation for that question because it was vaporizing a SOLID so it was sublimation there.</p>
<p>It was definitely at least TT</p>
<p>But apparently it was TTCE QQ</p>
<p>@immadinosaur That’s what I got. You can heat graduated cylinders as they are usually made heat-resistant. In certian labs, you need to heat the graduated cylinder or pour hot liquids into it.</p>
<p>lol, knowing what sublimation is gets you like 3 points on this test. i left one of them blank because i didnt think you would use a choice twice (for the first part of the test). i regret that so much now</p>
<p>But you should rinse with the titrant which I thought was the answr 
</p>
<p>And I didn’t know that. I suck at labs.</p>
<p>@Immadinosaur: You have to rinse a buret with the titrant before titrating in order to prevent dilutions from excess water.</p>
<p>@Princeton: CO2 is a nonpolar molecule even though it has polar bonds because of its shape. The polar “pulls” of the two O on each side cancel each other out.</p>
<p>@harharparis:
I put 5 moles down because Fe2(SO4)3 is soluble in water and dissociates into 5 particles</p>
<p>Here are the compiled answers y’all, add to this:
Chromium(VI) reduces to become chromium.
Iodine crystals sublime to form purple vapor
press. goes up as volume decreases
speed increases as volume decreases is TF
neutralization for limestone and acid
c –> co2 was oxidation
CO3 somewhere and CA+2 and H2O and CO2 was 2 I think
Are beta particles electrons? Wiki says so.
2K + H2O ----> 2K+ + 2OH- + H2
8L for decrease temp decrease P
It was 1.2 *10^24 so 2 moles answer: 13 grams
k=1x10^50 the C + D question
oxygen and hydrogen not HCl
555 kJ
O2 O3 allotropes
Na not in elemental
VO2 of vanadium</p>
<p>for CO2 linear one, it could really be TT or TTCE, it just depends how cb grades…</p>
<p>it didn’t say equal/similar polar bonds, though they are both C-O. if they were being tricky, it would be TT if not then TTCE</p>
<p>princeton34 & others,</p>
<p>I’m pretty sure Statement 2 said something like “its two polar bonds are arranged in a linear shape.” Not “the molecule has a linear shape.”</p>
<p>Princeton34: Not all linear compounds are non-polar, but the question stated that the polar bonds in the compound were arranged linearly, which means the polarity is counterbalanced, and so the molecule is non-polar. TTCE</p>
<p>Krazy: You said this:</p>
<p>“Forward reaction is endothermic BECAUSE the energy of the reactants is greater than that of products: FT”</p>
<p>If the energy of reactants>energy of products, then by products-reactants:</p>
<p>Heat of reaction MUST be negative. This means the reaction is exothermic. This may have been a typo on your part, but the reaction was definitely exothermic.</p>
<p>It was 1.2 *10^24 so 2 moles answer: 13 grams</p>
<p>^What’s that. I put 65 for the zinc one.</p>
<p>And what ws the beta particle question</p>
<p>agreed with Daisie</p>
<p>IMO it should have read symmetrically arranged for it to be TTCE</p>
<p>I agree with IvyCraze on the CO2 linear question.
But it’s safer to say that it was just TT since on May there was a similar question that had that molecules are nonpolar if they have a linear structure. (As we know in the case of HCl, that is not always the case.)</p>
<p>@llazar
yea, i said i put FT for that one because it is exothermic</p>
<p>yeah for the one with decay i didnt put a beta particle cause i wasnt sure whether a beta was an actual electron</p>