<p>This isn't exactly an SAT question, but it's a math-algebra question.</p>
<p>make x the subject of the formula</p>
<p>p=(x+3)/x</p>
<p>how do I solve this?</p>
<p>xp = x+3 (not laughing)
xp - x = 3
x(p-1) = 3
x = 3/(p-1)</p>
<p>x =/= 0 and p =/=1</p>
<p>^Hey, thanks.</p>
<p>Just one question; perhaps I don’t know the rules right…</p>
<p>px - x doesn’t eliminate x, right? How’s that? If though x - x is zero…</p>
<p>I factored so as to separate x. But I didn’t eliminate it.</p>
<p>X does eliminate x, but not when the numerator contains a “+” sign, and one of the terms doesn’t contain x.</p>
<p>Observe closely. The numerator is x+3 and x=3x or 3x. Hence, you cannot take x common in the numerator or you cannot just eliminate x from the numerator and denominator.</p>
<p>However, you can split the 2 terms of the numerator, which will lead to this –></p>
<p>(x/x) + (3/x)</p>
<p>In this case, (x/x) will end up canceling each other and the term’s value will be 1.</p>
<p>so, the final value is 1+(x/3)</p>