<p>^don’t you think you’re being harsh? Even I almost fell for it, but it was because of the wording and because my endurance was waning.</p>
<p>Yeah, is it really that hard to believe that some people mistakenly read median as mean? Calm down.</p>
<p>Were there two different experimental sections? I had four math sections, but only one had a grid-in response section.</p>
<p>I solely had one section devoted to that as well. Did some people have two?</p>
<p>Yeah. Some people had two. I only had one, though, and I’m pretty sure I had four math sections, but I may have had an extra writing and keep thinking it’s math because I had two math in a row.</p>
<p>If we solely had one section devoted to that, does that mean that math was our experimental section?</p>
<p>I had four math sections and it was quite prevalent which one was the “experimental”.</p>
<p>HELP PLEASE!
for the question about spelling TANYA, what was the answer for it?
i mean was it D?
i know that the answer is only I but i can’t remember if that was B or D
HELP PLEASE :(</p>
<p>It was I only. I believe that was option A.</p>
<p>The answer to the least number of right angles in a quadrilateral (or something of that sort) was 3.</p>
<p>Also, the f(x)/g(x) graph that said what is f(x) when g(6)=6…something of that sort…the answer was 5 because if you go up 5 and over to the y-axis, the y read 1…so thus, 1 X 6 = 6. Hope this helps!</p>
<p>I got A too.</p>
<p>For the quadrilateral, I would be surprise if someone miss that.</p>
<p>I thought the answer for that one was 3 not 5?</p>
<p>
Wrong. g(6) = 1 ≠ 6. Thus, we were looking for the x value where f(x) = 1. This was at 3, I believe. f(3)=6. 6*1=6.</p>
<p>@SLightManifesto
I wasn’t talking about the median, they already gave you what the median was (88). I was talking about the temperature on the 7th day. Thanks for the explanation btw, but I know what median is.</p>
<p>What a relief. I thought I was wrong.</p>
<p>All of these are the # of right angles in a quadrilateral EXCEPT:
A) 0
B) 1
C) 2
D) 3
E) 4</p>
<p>I really hope no1 missed this… ;)</p>
<p>^ I left that one blank. I have no clue.</p>
<p>
</p>
<p>I was a little harsh but it was getting annoying. How can half the people on this site have made a mistake on that question? I don’t get what “wording error” you guys are pointing out. Essentially what I am asking: What was your logic after sorting the numbers to figure out that the median was 93?</p>
<p>^Boston, I just drew it out. I drew out quad’s with 0 right angles, 1 right angle, 2 right angles, and 4 right angles, but I couldn’t possibly get one with 3 right angles without having to make a 4th.</p>
<p>A quadrilateral can not have 3 right angles. If it does, than the fourth angle has to equal 90 degrees.</p>
<p>For the number of right angles can’t be possible in a quadrilateral:
answer is 3 because a quadrilateral has 360 degrees. If there were three right angles (90 degrees) then the fourth angle would need to be a right angle in order to add up to 360; therefore, only three right angles wouldn’t work.</p>