<p>“(x-y)^2>0 (choice II) will be positive, out of 3 options”</p>
<p>Wouldn’t (y-x)^2 also be positive… since it is being squared??</p>
<p>^ I don’t think that was an answer choice though</p>
<p>i just realized a completely stupid mistake…</p>
<p>in the temperature question, they were definitely looking for the median and not the mean? -.-</p>
<p>actually it stated that 88 is the median, but it asks what is the temperature for the 7th day.</p>
<p>@cookiemonster7
For that question i only remember two options,
x^2-Y^2 must be positive
and (x-y)^2 >0</p>
<p>@ laurora
yeah… i thought it was mean at first, but i thought for that for a moment haha</p>
<p>i remember, but was 88 the answer? i put 93…</p>
<p>@davissiu
haha oh, well i guess i didn’t think then =P</p>
<p>@jerrry4455
if u put those number from least to the greatest
you will get sth like 80 83 85 blank (7th month) 90 93 95
(i made up those numbers coz i can’t rmb exactly what that was)</p>
<p>since they said 88 is median, so then blank is 88 which is the temp for 7th month</p>
<p>What was the (x-y)^2 question?</p>
<p>I vaguely remember it, but I remember the only answer being (y-x)^2, because you had to account for negative numbers.</p>
<p>@davis
The x^2-y^2 was an incorrect answer.
It does not have to be greater than 0. </p>
<p>THe only correct option for that question was 3.</p>
<p>@Jwman 92
i know, someone was asking for the options</p>
<p>@luminouz
The question was if x>y, which of these <em>must</em> be positive?</p>
<p>@davis
Ah ok, just making sure ;)</p>
<p>@davis I agree!!
And anyone remember the choices for the (x-y)^2 question</p>
<p>@davissiu 88 is the answer. It was missing from the data set.</p>
<p>It was missing from the data set but they said it was the mean and asked to find the 7th day temperature (93). I’m very certain</p>
<p>@jerrry4445
yeah thats what i said haha</p>
<p>@cookiemonster7
i am pretty sure they said median is 88</p>
<p>Does anyone remember if 0.2 was one of the choices for the question with this answer: </p>
<p>0.4 probability of picking a value that is also in the second set</p>
<p>It was <em>definitely</em> the median. I remember because I completely blanked out and spent ~10 seconds staring at the word and trying to think of what it meant.</p>
<p>@Lucas.</p>
<p>The answer is (y-x)^2 then. (y-x) will always result in a negative number, and it becomes positive when it’s squared. The compiled answers lists the answer incorrectly as (x-y)^2</p>
<p>Yes yes my bad it was the median. that was a typo. It gave 6 temps and said the median is 88, find the temp on the 7th day.</p>