<p>@davissu</p>
<p>it must work for all number that work n not just 8.</p>
<p>@davissu</p>
<p>it must work for all number that work n not just 8.</p>
<p>Was the divisibility problem experimental?</p>
<p>
</p>
<p>Kameron the largest electoral difference answer is already on the list as “B was most change in votes from 2002 to 2004”</p>
<p>9/25 is Oak to Maple ratio
xz is the smallest
c = 0 when k = 3</p>
<p>I don’t remember those questions at all. Can someone remind me of the context?</p>
<p>if n is a number, and 2n is divisible by 8, which must be true?
I. n is divisble by 8
II. n is divisible by 4
III. n is divisible by 2 </p>
<p>edit;
you had to get the lowest possible value, otherwise you could’ve chosen 8, 16, 32, etc (they all are divisible by 8)</p>
<p>2n (if n was 4) would be 8, so 8 is divisible by 8.</p>
<p>4 is not divisible by 8, so it’s just II and III.</p>
<p>if n is a number ,and 2n divisible by 8, which must be true.</p>
<p>let say N=4, so than n is divisible by 2 and 4, </p>
<p>if N=8, n is divisible by 2 ,4 and 8 ?</p>
<p>i agree with strabearries…i have no idea which questions those answers are referring to =P</p>
<p>@Jersey13: Ooops! Nice catch.</p>
<p>Can someone confirm the divisibility problem wasn’t experimental?</p>
<p>for the x-intercept of the vertex, after finding ‘k’, the equation came out to be x^2 + 8x + 15; thus, the x-intercept is (-3, 0), not (5,0)</p>
<p>9/25 is Oak to Maple ratio</p>
<p>on the oak maple question, they give you a diagram where maple is 50% and sth else is 32%, and oak is X%, then they ask you what is the value of the number of oak / number of maple</p>
<p>I’m pretty sure the divisibility problem was not experimental.</p>
<p>
</p>
<ol>
<li><p>There was a pie-graph showing 50% of the trees in a city were Maples. 32% were “Other”. And there was no label for Oak (but a simple 100-50-32 would give you that it was 18%). Then you just simplified 18/50 -> 9/25.</p></li>
<li><p>x < 0 < y < 1 < z . Which of the following would be the smallest? And the answers were stuff like x^2, zy, y^2, etc… the answer was xz.</p></li>
<li><p>There were 2 equations: a = .5(6b - 6) (or something along those lines) and c = a - 3b + 3. If you distribute the first equation and manipulate it a little, you get a - 3b = -3. Then you just replace that into the 2nd equation to get c = -3 + 3 = 0.</p></li>
</ol>
<p>
Wrong. IT came out to -8, I believe.</p>
<p>@davi
it asks which MUST but correct, if any n chosen will be divisble by 2 and 4, because 4 is the lowest, 8 will not be correct if n is 4</p>
<p>Thanks davis and manifesto.</p>
<p>EDIT</p>
<p>Another question.
Does anyone remember if 0.2 was one of the choices for this question: 0.4 probability of picking a value that is also in the second set</p>
<p>@davis: it must work for ALL cases, not just for a few.</p>
<p>confirm, not experimental</p>
<p>answer was II and III</p>
<p>I answered II and III as well.</p>
<p>Divisibility wasn’t experimental. n has to be divisible by 2 and 4</p>
<p>@ thrill3rnit3, jjtheairplane
thank you, got it omg…
so probably i have like -4 sth like that</p>