<p>How would you solve this question</p>
<p>The two circles x^2+y^2=1 and (x-sqrt(2))^2+(y-sqrt(2))^2=1 are tangent to each other. What are the coordinates of the point of tangency?</p>
<p>How would you solve this question</p>
<p>The two circles x^2+y^2=1 and (x-sqrt(2))^2+(y-sqrt(2))^2=1 are tangent to each other. What are the coordinates of the point of tangency?</p>
<p>Son is taking the test tomorrow, this is his explanation:</p>
<p>We know that they are tangent and that one circle is the unit circle. The other circle is shifted equaly up and right. The angle between the x-axis and the line conecting the circle centers is 45 degrees. This line will intersect with the point of tangency. So the point is (cos 45, sin 45) or (1/sqrt2, 1/sqrt2). The math checks out.</p>
<p>Tell your son thanks. Here is another one
What is the volume, in cubic centimeters, of a rectangular solid that has faces with areas 2, 4, and 8 square centimeters?</p>
<p>nm I figured it out. For those who want to know:
There will be a length, width and height. Let lh=8, lw=4, hw=2. Multiplying all together you get l^2 x w^2 x h^2 =64. Taking Square root of both sides gives lwh=8</p>