November 2012 SAT Math Level II Discussion

<p>Hey, I really don’t wanna be searching for answers all day. Soo I’ll literally pay you guys up to 15$ for questions and answers you remember from todays test. Check it out and keep on adding, I want to get the whole test</p>

<p>View here</p>

<p><a href=“https://www.■■■■■■■■.com/questions/361?title=What+are+the+answers+for+the+SAT+Math+II+Test%3F[/url]”>https://www.■■■■■■■■.com/questions/361?title=What+are+the+answers+for+the+SAT+Math+II+Test%3F&lt;/a&gt;&lt;/p&gt;

<p>^Sorry but I don’t feel like joining that website. Btw, that dude with the ghost pic is wrong 2^x = -1.7 means x=.3 or something like that I think idk I don’t feel like grabbing a calc (unless he means a dif question). And vectors is 11… </p>

<p>@ silentbullet anyway look at this pic. <a href=“http://img.sparknotes.com/figures/7/76cc050742a1118db58ed8e038b2f465/vectorsum2.gif[/url]”>http://img.sparknotes.com/figures/7/76cc050742a1118db58ed8e038b2f465/vectorsum2.gif&lt;/a&gt;
Pretend that the v solid line is 4 and u solid is 8. Now forget the solid line and use the dotted line instead. In other words shift v to the right and keep it connected to u. Because the angle between v and u solid lines is 50. The angle between v dotted and u spotted is 130. Now use 4, 8, 130 deg to find u + v. dotted v solid u and u+v is a triangle so law of cosines works. a^2 = b^2 + c^2 -2bcCosA
Or… again use my othe method. I used both methods to check the answer during the test.</p>

<p>How do you guys think the curve is looking for the test?</p>

<p>Does anyone remember how many (m,n) you can get when they are between -4 and 4? It had to do with exponents</p>

<p>What would the score be around if 40 were right, 3 were wrong and 7 were omitted?</p>

<p>hey guys, do you remember the question with the symbols standing for a particular operator? There was an example given which said “…= 2 1/2”. Since there is no + sign in between 2 and 1/2, the 2 cancels and “=2 1/2” = 1. Many students thought that it would be 2.5 but actually it is 1. Working with 1 doesn’t yield a correct answer choice (only when you use 2.5). Let’s see what collegeboard says … :-)</p>

<p>How do you do #3?
It was an open box with dimensions.
Do you just multiply those 3 dimensions?</p>

<p>@bradsta: i just rememer having an equation n/m=0.5 there were four answers possible (1/2 2/4 -2/-4 and -1/-2) hope this helps</p>

<p>@albr There doesn’t need to be a plus sign, 2 1/2 is a mixed number, it’s not multiplication unless there are parentheses or a multiplication sign. 2 1/2=2.5, and the answer in the end was either 3 or 4 (can’t remember the numbers but choice C i think).</p>

<p>@smartdude Yes, you just multiply the dimensions to get the volume</p>

<p>Hecka failed. I didn’t want to leave about 15 blank so i guessed answer choice B for all of them… bad move good move? anyone !!! :(</p>

<p>Crap I just hope I get above a 700…</p>

<p>What was the answer to the depth of the lake or whatever? I thought that h could only be a max of 3 for there to be a solution and somehow got the answer to be 4.2 or 4.3 (whichever one was different from the one in the equation) but… after graphing it seems as though the difference is 8.5. Anyone else get a for-sure answer?</p>

<p>I got 8.7-4.3 = 4.4 for the lake problem.</p>

<p>What was the lake problem?
Also what was the answer to that period question?</p>

<p>Did anyone get 0.1 for the probability question?</p>

<p>^ Lake was 4.4. Period was 2pi. And I think 0.1 was for standard deviation.</p>

<p>Isn’t the probability question 2/9? Why is it 4/9?</p>

<p>I do not even want to discuss the stupid maths -_-</p>

<p>|x/x| - |x|/-x?</p>

<p>@Chemist
Lake was 8.4</p>

<p>@ExeterH0peful Darn, I think you’re right. </p>

<p>Can anyone confirm these?</p>

<ol>
<li> Function not defined at x = 1</li>
<li> Parallel lines: k = m</li>
<li> Which function is same as inverse: I. and III. only</li>
<li> Standard deviation of boxes were the same after added weight (0.1)</li>
<li> Probability of call: 4/9</li>
<li> Length of line segment: 1 – cos(theta)</li>
<li> If x = arctan y, then sqrt(1 – y^2) = |sec(x) |</li>
<li> Choosing samples: 7280</li>
<li> Assigning operations to symbols: 3</li>
<li>x = x^2 + bx + c: 2 solutions</li>
<li>As x approaches 3/2: y increases without bound</li>
<li>Range of function: less than or equal to 2</li>
<li>3 consecutive numbers: divisible by 2 and 3 (I. and II. only)</li>
<li>Equation for points equidistant from (1, 1, 3) and (1, 2, 3) in xyz coordinate plane: y = 3/2</li>
<li>Folded paper: 10</li>
<li>Height of cone: 24.84</li>
<li>Mo/2^t</li>
<li>Area doubles by 4</li>
<li>Vector problem: 11</li>
<li>Area of triangle bounded by sine curve: pi/2</li>
<li>Finding the constant m: 2</li>
<li>Period of trig function: 2pi</li>
<li>Difference between maximum and minimum values of function: 8.4</li>
<li>Mean of the frequency table: 21.67</li>
<li>Probability of picking the sum: 0.06</li>
<li>Compound interest: $3685.57</li>
<li>Shifted parabola: f(x) = (x – 2)^2 + 2</li>
<li>Prime number that is a counterexample: 19</li>
<li>Slope of the line with the midpoint: -1</li>
<li>Exactly two real roots: (x^2 – 1)(x^2 + 1)</li>
<li>Deviation was 8.4</li>
<li>g(x) is 2x – 2 for combination of functions</li>
<li>If tan^2(x)=1.0913, cot(x) = 0.9573</li>
<li>Question with log: 1.2</li>
<li>Number of integers between -4 and 4, inclusive, that satisfy 2^m = 4^n: five</li>
<li>Box with three dimensions: 96</li>
<li>|x|/|x| - |x|/-x: 2</li>
</ol>

<p>@ExeterH0peful </p>

<ol>
<li><p>Which function is same as inverse: I. and III. only. No, this is defintely 1 only. </p></li>
<li><p>Probability of picking the sum: 0.06-- I thought the answer choice was 0.6?</p></li>
<li><p>Shifted parabola: f(x) = (x – 2)^2 + 2-- Was this one moved over 3? </p></li>
<li><p>|x|/|x| - |x|/-x: 2-- I don’t recall this question, but I’m pretty sure it was 0…</p></li>
</ol>