<p>most colleges want writing
but no it doesn't affect your composite score</p>
<p>what choice was -1/2 and what question are were talking about?</p>
<p>-1/2 was choice A and refers to the second to last question.</p>
<p>my god, that test was waaaaay harder than the september math test. i actually had to guess on a few.</p>
<p>so, im getting the general concensus that most people put "-1/2" for the "triangle area/vertices" question?</p>
<p>...if so, whew</p>
<p>dang i was gonna guess -1/2, i think i ended up guessing 2 as the proctor called time. Math sucked, no time.</p>
<p>What was the actual question for that?</p>
<p>-1/2 was choice B, not A</p>
<p>it was probably a different test format, coz i explicitly remember changing my answer to A, but that's besides the point.</p>
<p>kalamity, i agree, this math test was so much harder than september's. I got a 34 on that one, but idk how i did on today's test...</p>
<p>I had version 67A, they should've been similar.</p>
<p>Anyone remember the odd interger one, then find the sum of the two smallest or something?</p>
<p>the question was something like the Sum of all three odd integers is K and then they had equations with that variable... one was like... K-2 or/and K-1 and (2k/3)-2 ... thats all i can remember...</p>
<p>I remember it vaguely knifey. It was 3 sequential odd integers, and then it asked something about what the first two odd integers added up to.</p>
<p>I can't remember the answer choices though, but I remember when I calculated it, it came out right, so I'm pretty sure I got it right.</p>
<p>Anyone remember what they put? I did it four times and didnt get anything like they had, but K-2 was closest to my answer so i guessed that.</p>
<p>K-2 is NOT the answer, if I remember correctly.</p>
<p>I would need the exact question though to be able to be sure though.</p>
<p>2/3k...........</p>
<p>hmmm... maybe it was like: There are three positive odd consecutive integers. The two largest (or all three) odd numbers equal K. Find the equation that would equal the lowest odd number.</p>
<p>a) (2k/3)-2</p>
<p>b) forgot</p>
<p>c) k-2</p>
<p>d) forgot</p>
<p>If it said all three integers equal K then...</p>
<p>1+3+5=9=k</p>
<p>Lowest two integers= 4</p>
<p>using (2k/3)-2</p>
<p>... 2(9)/3-2= 18/3-2= 6-2=4... answer= a)</p>
<p>i think it was A... almost positive</p>
<p>Ah, now I remember the question. Sorry, it wasn't K-2, I think it was 2/3K - 2.</p>
<p>I used 5, 7, 9 to figure it out.</p>
<p>just use 1,3,5</p>
<p>you can't
then you get A-2...that is precisely what ACT wants you to use</p>
<p>Use 1,3,5 and confirm with 11,13,15
answer is A</p>
<p>Yeah, that would work too I think, I just don't like using 1 in my substitutions, because it can skew the results. But not to be a flip-flopper, but I agree with you islanders that it is choice A.</p>