<p>woot... got the answer correct...</p>
<p>using 1,3,5 yields 2k/3 -2 and k-2</p>
<p>1MX, good eye.</p>
<p>Oh well, two down on math so far. Those were the two I wasnt sure about/guessed on thought, so I'm feeling pretty good!</p>
<p>i thought it asked for the sum of the first and last numbers...in that case it would be 2k/3</p>
<p>maybe i misread the question</p>
<p>I wish the ACT had more logic problems/word problems - those are what I'm best at :(</p>
<p>lol walt... take the sat... and then COME BACK!!! =p</p>
<p>Eh, I took the SAT - I probably got all of the word/logic problems right, and I rock at algebra. But... I'm (somewhat) weak in plane geometry and trigonometry, and so the last 10 problems or so kick my ass on the ACT</p>
<p>1MX, well if u have a great photographic memory, what was the answer to 56?
I dont remember the problem, but i got -3/4
Ummm, anyone wanna give answers for 57-60 (letter please, cause i guessed b on all of them cause i was running out of time.</p>
<p>How much would minus 8 be? like 29 or somethin?</p>
<p>According to the ACT practice test booklet, -8 = a 31</p>
<p>you got it wrong BIGTWIX, the answer to 56 was not -3/4 cuz the angle was coterminal. I was going to put that (C or H) but then I saw theta was a coterminal angle. </p>
<p>And I think 58 was D and 59 was E. I actually did those instead of some of the earlier ones. They were pretty simple compared to the rest of the test.</p>
<p>I don't know if it was me or was this the hardest math test administered by the ACT. On all the practice tests I've had like 5-10 min left over. On this one I had like 3 questions left blank.</p>
<p>-1/2 Thank God I Guessed It</p>
<p>for the one with 110 as the central angle, can you say it's 35 for the other angle or is there not enough information?
also for cos theta what did we decide .. here is what i did</p>
<p>you have a triangle with sides -3, 4 and 5. cos = adj/hyp, so you do -3/5. I realize cosine should be positive in this quadrant but there was no 3/5 which I really would've preferred to use ... was that the right answer</p>
<p>and can someone explain the slope = 1/2 .. I thought it should be undefined (if you think area of a triangle is .5 * b * h .. the height and base lengths would not change) but that was not an option.</p>
<p>and is -2 going to be a 36? I hope so I got a 36 last time and it was so much easier ...</p>
<p>It was 35 because each side was a radius therefore they are both equal.</p>
<p>(180-110)/2 = 35</p>
<p>it was -1/2 cause in order to maintain a constand height, it needed to move along a line parallel to AB. AB was -1/2.</p>
<p>What was the answer to the ray through point O question? Was it just me or was there two answers?</p>
<p>Through process of elimination, I got ray CD for that one.</p>
<p>please 1MX... explain how 1,3,5 results in both (2K/3)-2 AND K-2... that makes no sense. 1+3+5=K, therefore K=9, and 9-2=7, not 1+3, which =4, the correct answer. 2(9)/3=18/3=6 then 6-2=4, the correct answer... that was such an easy question... use 1,3,5</p>
<p>ray CD....</p>
<p>ok, 58 was the cos(theta)=4/5, not 56. 56 was on the top left of the last two pages and was the consecutive odd integer problem. </p>
<p>Islanders..it may not have been k-2, but there certainly was two options if 1,3,5 were chosen. That's just the nature of the ACT. I'm not going to argue, but there were two possible options when 1,3,5 were chosen</p>