<p>the two capacitors were a distance 0.2 metres apart, and a certain voltage was going through them. u had to find out the charge in the middle on a particle (q) (i.e. 0.1 metres from either plate)</p>
<p>I remember using Q=v/d, and getting 4.9 * 10^something</p>
<p>ok ill add that to the list
did anybody get the 6 screens and light question there were two questions for it
one asking where light cannot be seen
and another asking where white light can be seen
we need confirmation!</p>
<p>Sorry, I can’t remember what I put. But can you please confirm the question about the Moon and the Earth - was it the point that is 2nd closest to the Moon?</p>
<p>Do you remember what you put for the question with two coils and one has an induced current going right, so the other one has an induced current going left or right and the magnetic field is right or left I dont know but I know its either A or B What did you put?</p>
<p>2 charges that +q and -q and you have to find a point where it will be directly west…and for the velocity graph of the frictionless inclined plane what did you put? I know acceleration has to be straight line and displacement is upside down parabola…</p>
<ol>
<li>the inclined plane then loop : when move the ball higher, the velocity increase</li>
<li>a charge moving in magnetic field: the change in kinetic energy equals 0</li>
</ol>
<p>Two wires with currents: The magnetic field halfway between the wires is perpendicular to the page. Using the RHR for both wires, both of the fields they create point into the page at the halfway point.</p>
<p>Ball slides down, then into loop: Don’t you need to know the radius? If the ball goes too fast it’ll fly off the loop…</p>
<p>+q/-q: The answer was the point halfway between the charges (B, I think).</p>