October 6 SAT math

<p>
[quote]
andrea: 13.5</p>

<p>9 x 1.5 (the first x intercept)

[/quote]
</p>

<p>oh, are you sure the x intercept wasnt 3? for some reason i thought it was. i know that nine was the y intercept, but i thought three was the x intercept.</p>

<p>and did anyone else get 12 as a grid in answer.</p>

<p>Okay, thanks. Let's hope it's right!</p>

<p>Right now, I'm at 1 omit, 2x. Any estimates? I really hope I don't get any more wrong. Math was always my weakest section. I went from 650 to 620, and breaking 700 would be a huge deal for me.</p>

<p>There are two x-intercepts, the lower value x was the length of the side. Therefore 1.5x 9</p>

<p>1 omit and 2x = 730-750.</p>

<p>Ha...I wish my score was that good. I got really distracted on the last section and ran out of time. I'm guessing 4 wrong, and 1 omit. :(</p>

<p>anyone remember the one about the parabola (roman numeral) like how many times it can cross the xaxis?</p>

<p>14.7 was 90% 15 and 10% 10, whats the mean?</p>

<p>Yeah....I've been pondering over the same thing as andreaaaaaa. Everyone on this board seems to be confident that the last grid-in answer was 27/2, but I got 27 also! </p>

<p>I plugged the equation into the quadratic formula and got 3 as my x-intercept...how did everyone else get 1.5 as theirs? "a" for the "2a" in the denominator was "2" - therefore the denominator was 4. And for the numerator, I got 12. That would equal 3 for the answer. (And then 9 x 3 = 27 for the final answer).</p>

<p>Did I make a mistake somewhere...? o.o</p>

<p>For the grid in that the answer was 2... does anyone remember what the question was?</p>

<p>You mean the one about a cylinder and a cone?</p>

<p>(And thanks for the estimate, Duper)</p>

<p>as for the 1.5, i graphed the quadratic in my calculator and just found the zero that they were asking for and it was 1.5</p>

<p>There were 2 x intercepts: 1.5 and 3. 3 was not the one that bounded the rectangle.</p>

<p>I don't think I have any wrong so far! I don't remember if I omitted anything... This is my 3rd time, and I want to say I got an 800 in SOMETHING.</p>

<p>And for some reason, I recall getting 48 for that trapezoid one (two 6x8 triangles with a shaded one in between), but I also remember checking it several times and getting the same answer (and I did it just now and got 50).</p>

<p>I'm so happy about some of them... esp. the system of equations one. I resorted to check-and-check on a few, and I got the right answer on the first try!</p>

<p>merpug, the quadratic crossed the x-axis at both 1.5 and 3. 1.5 was the one you were supposed to use</p>

<p>Damn... I also forgot to divide 6 by 3...... z=2 was too obvious... damn it!</p>

<p>if nobody posted it yet (i lost track) parabola was 2x^2 -9x+9, so
y-intercept is 9
(2x-3)(x-3)=0 gives x=1.5 or x=3. x=3 is on the right side of the parabola's axis,
you have 9x1.5 rectangle.</p>

<p>does anyone remember what the "givens" were for the area of the shaded region one</p>

<p>can someone give me an estimate for 2 omits and 1 wrong? i'd really appreciate it! i'm really hoping for a high 700 this time; i felt this month's math section was leagues easier than may's!</p>

<p>we were supposed to find the area of the triangle under that curve(or function, or whatever it was), right?
1.5*9/2 = 6.85 was what i had.</p>

<p>for the one about h(x)=h(2x) was the answer 2
and the one about f(k)-k=0. was it -1</p>

<p>Anyone have an explanation for the question about the least number of people claimbing and swimming?</p>