<p>
[quote]
There were 2 x intercepts: 1.5 and 3. 3 was not the one that bounded the rectangle.
[/quote]
</p>
<p>okay, thanks. dangggggggg.</p>
<p>so, did anyone get 12 as a grid in?</p>
<p>and what was the answer to the systems one?</p>
<p>nah, the shaded triangle one.</p>
<p>chinn- yes to both</p>
<p>The experimental section contained the r^2st = 200
as well as the</p>
<p>"Two points that lay on a circle are (10,2) and (10,10)" What is the X- coord of the center of the circle? (10, 11, 12, 13, or 15) </p>
<p>as well as the</p>
<p>"We have two parallel lines with a triangle between the lines. Which angles add to 180 degrees?" (Roman numeral question)</p>
<p>Anyone remember the grid in question that had 145 as an answer?</p>
<p>art_star, I would say 740.</p>
<p>chinnu_4 I got both 2 and -1 for those two questions</p>
<p>OHHH doi....yes, soon after posting I realized what I must've done wrong....I forgot that that there would be two <em>positive</em> x-intercepts....I was thinking one would be negative, so I immediately used the first positive one I got. Darn >.<. That was stupid XD. Thanks guys!</p>
<p>a532, it was finding an obtuse angle between 2 triangles and their angles given</p>
<p>The answer was 2. h(2) = h(4) = 0</p>
<p>And -1</p>
<p>
[quote]
Anyone have an explanation for the question about the least number of people claimbing and swimming?
[/quote]
</p>
<p>okay, from what i remember: 5/6 out of 240 can swim. so thats 200 that can swim. now, the question says that one third of the campers take climbing lessons. i cant remember exactly how it was worded, but you had to assume that EVERY camper who couldnt swim (40 campers) took climbing lessons. (1/3) of the campers took climbing lessons, so thats 80 out of 240, and 40 of them couldnt swim. so that leaves 40 that could swim.</p>
<p>it was something like that.</p>
<p>THE systems of equation was 2 (the one with x y z). TWO is the answer, A.</p>
<p>there is a debate about the swimming one....i still think it's 80 since it asked what's the least amount that can swim and climb...and climbing had only 80 people total...so 80 people know how to climb, and 80 people (a small fraction of all that swaM) could swim</p>
<p>Huh, that's funny....I didn't get that 1st experimental question in my booklet (the "Two points that lay on a circle are (10,2) and (10,10)" What is the X- coord of the center of the circle? (10, 11, 12, 13, or 15)" one.) I assumed everyone got the same experimental questions..</p>
<p>And yeah I got 145 for one (and am <em>positive</em> that it's correct.)</p>
<p>does anyone have an explanation of how to do hte cone/cylander problem?</p>
<p>3, 9, x, x is average, x=6</p>
<p>blocks rearranged, what's the new area -stays the same!
rectangle with a dot rotated - I and II only</p>
<p>average cd price [.9n($15) + .1n($12)] / n = ...</p>
<p>two sets: chances of positve sums? can't remember 4/10=2/5?</p>
<p>1/3(pi)(r^2)h vs (pi)(r^2)h</p>
<p>There's three times as much volume in the cylinder. The contents of the cone would fill it up 1/3 -- to 2".</p>
<p>chinnu_4 those are right i think</p>
<p>the question with the interception at 1.5, isn't the answer 6.75 or something?
1.5 * 9 / 2
i thought the question asked for the area of the triangle in it. did i screw it up? :(</p>
<p>hey can someone explain to me why the last math grid-in was 13.5?</p>
<p>It was a parabola that formed a triangle. But the triangle had legs of 9 and 1.5, so shouldnt it be 9*1.5/2 = 6.75?</p>
<p>
[quote]
does anyone have an explanation of how to do hte cone/cylander problem?
[/quote]
</p>
<p>the radius and the height were 3, and 6, on both of them. so you find the area of both of them, and divide the cylinders volume by six, because its six inches tall. the cone equals the cylinders volume divided by six, times two. so the answer is two inches.</p>
<p>for the one that was like... you have 90 cds and they cost 12 dollars and 15 dollars im pretty sure the answer was E</p>