<p>can sb phrase the entire problem again? or at least gimme the values that were given for the cone and the cylinder?</p>
<p>the radius was three, and the height was six, for both of them. can anyone else confirm? i know that the height was six for sure. but the radius was three, right?</p>
<p>yeah radius was three and height was 6. and im pretty sure it was 2.</p>
<p>yeah, it was two. you just have to plug the numbers into the volume equations, and then divide.</p>
<p>see.. heres the dilemma.. its not that i didn't get 2.. I did..</p>
<p>but i can clearly remember the question as.. "what is the depth of the cylinder after the water has been added?"</p>
<p>as opposed to.. "What is the height of the water when added to the cylinder?" </p>
<p>do you understand what i am saying?? i mean i might be wrong.. yet on a number 20 question.. it just seems way too easy for you be able able to figure it out by setting the volumes equal to one another then divide. </p>
<p>Originally i got 2 just like you guys.. but 2 is the height of the water in the cylinder.. i read depth so i put 4 since i know the cylinder's height is 6.. iono if that makes sense.. i might of gotten it wrong..</p>
<p>
[quote]
"what is the depth of the cylinder after the water has been added?"
[/quote]
</p>
<p>well, if that was the problem, then the answer would have been six. and that REALLY seems too easy, because its given. and it wasnt the last grid in, it was the third to last.</p>
<p>I really disagree with (x-3)^2 as the answer:</p>
<p>If you split the diagram into a right triangle and a rectangle, the lower rectangle had sidelength 3 and length y. The length of the height of the triangle was equal to that of the base, which was x.</p>
<p>so, the area of the triangle plus the area of the rectangle is 1/2 x^2 + 3y giving your answer. I'm pretty sure about this one myself-can more people clarify?</p>
<p>A quick calculation says that the volume of the cone is 18pi and the volume of the cylinder is 54pi. So, if you fill the cone with a liquid, the liquid will have a volume of 18pi. And if you pour that liquid into the cylinder, it will still have a volume of 18pi. So, 54pi-18pi=36pi. Therefore, we construct the equation 36pi=r(squared)(pi)h, and we find h=4. So, when we add the water, the distance from the water to the top of the cylinder is 4, and the water takes up height 2. So, the problem is what ON EARTH did the problem ask for??!!!</p>
<p>whatiscollegeok: you are wrong. the x referred not to the side of the triangle, but to the side of the triangle + the one taken up by the rectangle. if you split it, you see that you have to subtract 3 in order to get the side of the triangle. i got what you said at the beginning, but then i realized i was wrong.</p>
<p>If you're sure the x referred to the length of the entire side including the bottom part of the rectangle, I'm wrong.</p>
<p>I know I did the problem using x as the side length of the triangle....it's most likely i tricked myself by dividing the polygon too quickly and forgot to sutract the area =/ Thanks for your explanation.</p>
<p>check this diagram...as you can see, x notes not the side of the triangle, but the side of the ENTIRE thing...triangle +3...so you HAVE to subtract 3 to find the side of the triangle..</p>
<p>go here to see the diagram
<a href="http://www.box.net/shared/ndft7absrt%5B/url%5D">http://www.box.net/shared/ndft7absrt</a></p>
<p>
[quote]
"what is the depth of the cylinder after the water has been added?"
[/quote]
</p>
<p>the water added doesnt affect the depth. for example, a pool, even if its empty, is five feet deep. adding four feet of water doesnt make it one foot deep. its still five feet deep.</p>
<p>Did it ask for the depth of the cylinder or the depth of the water tho??!!!</p>
<p>the depth of the water.</p>
<p>debate_addict, don't confuse yourself. You think too complicated.
it asked for the depth of the water, the depth of the cylinder was actually given. i think that was the tricky part : you had to ignore the given depth (height) of the cylinder (which was 6)</p>
<p>you did an extra step by subtracting 18pi from 54pi. this extra step probably confused you. </p>
<p>How i did the problem is:
volume of the cone = 18 pi
volume of the cylinder = r^2 * pi * hegiht, which is 3^2 *pi * h
The importatn thing here is, you have to IGNORE the given height (6), since HEIGHT was what you have to solve for.</p>
<p>so you just plug in the numbers
18 pi = 3^2 * pi * h
18 pi = 9pi * h
18 = 9 * h
therefore, h =2</p>
<p>Can somebody explain me the problem with the function and the graph. y = f(x). if f(a) = f(2a) whats a?</p>
<p>what was the 2nd to last grind in problem... the one where the answer is 63?</p>
<p>Wats the 256 for? is that in the grid in. Wat was the exact question... doe anybody remember</p>
<p>the 256 i believe was a circle inside a square, the square sides was tangent to the circle, so incribed....and the circumference of the circle was 16pi and you had to determine the area of the square,</p>
<p>Circum: 16pi
D*Pi = circum
Dia=16 which is one side of the square, all sides are equal, so 16^2 = 256, so that;s the area of the square.</p>
<p>Antonio the answer is 2 because f(2) and f(4) both give you 0</p>
<p>guy i didn;t read thorught the whole tread for good reasons, but did anyone answer the question: y=F(a) what is like F(2a). i couldn;t figure that one out...and time ran out.</p>