<p>TheMathProf, based on the free response questions and what you have heard regarding the multiple choice what do you think will be the approximate scale/curve(neccesary raw score) for a 5?</p>
<p>For 3c, I had V = 60000 + integral(0,25) (2000 - R(t)) dt.</p>
<p>I've been having trouble with the points allocation for this question, but I'm guessing that there are three points: one for the limits, one for the integrand, and one for the rest of the equation. I have no idea if that's accurate at all, because the limits point seems to double reward you for finding 25 from part (b), but I'm not sure where else to put the 9th point. Maybe it's 2 points for dV/dt in part (a); I only have it as one currently.</p>
<p>My answers:</p>
<p>1(a) -> 4</p>
<p>(b) -> integral from .53918 to 1.6751 of (-2 - (x^3 - 4x))</p>
<p>(c) -> integral from 0 to 2 of [(sin(pi x) - (x^3-4x))^2] = 9.978</p>
<p>(d) -> integral from 0 to 2 of [(3-x)(sin(pi x) - (x^3 - 4x))] = 8.370</p>
<p>2(a) -> 8</p>
<p>(b) -> 155.25</p>
<p>(c) -> 3</p>
<p>(d) -> 973</p>
<p>3(a) -> .038</p>
<p>(b) -> t=25</p>
<p>(c) -> integral from 0 to 25 of (2000-400sqrt(t)) + 60000</p>
<p>4(a) -> (3,-10)</p>
<p>(b) -> 3</p>
<p>(c) -> decreasing</p>
<p>(d) -> [0,1] and [4,6]</p>
<p>5:</p>
<p>(a) -> slope field! </p>
<p>(b) -> -e^((x-2)/2x) (I forgot the +1. Bleh.)</p>
<p>(c) -> -e^(1/2) (Again forgot the +1...)</p>
<p>6:</p>
<p>(a) -> 3 e^(-2) - x e^(-4)</p>
<p>(b) -> x = e</p>
<p>(c) -> x = e^(3/2)</p>
<p>(d) -> negative infinity</p>
<p>The free response were not difficult; they were simply "different" from what has been standard on the past, although very slightly. In my opinion, to get a 5 it will remain at like 70-72, because I'm pretty sure the nation didn't do THAT bad that they would drop it to like 66 again.</p>
<p>I don't have a good guess with regards to cut scores. I gave a tongue-in-cheek 70+ as an answer on another thread, and it seems as good a guess as any, but I don't really have any special info there.</p>
<p>Wow, I pretty much got wrong answers for everything except #1 and #2.</p>
<p>This test was so easy! I finished to calculator MC in 20 minutes and took a half hour nap.</p>
<p>wait which one was the trapezoid question.. and did you have to set it up into 3 equal sub intervals?</p>
<p>The trapezoid question was 2b, and the intervals were unequal. This is how I did it, I dunno if it's right:</p>
<p>.5[(L(0)+L(1)) + 2(L(1)+L(3)) + (L(3)+L(4))]</p>
<p>=</p>
<p>.5(120+156) + (156+176) + .5(176+126)</p>
<p>=</p>
<p>621</p>
<p>Divide by 4 to get the average = 155.25</p>
<p>yeah ok that's what i did except messed up the part that doesn't involve calculus.. dividing by 4.. will i get some credit at least for getting 621?</p>
<p>Nobody knows for sure yet, but I would think so.</p>
<p>would you get any credit for doing ( (LRAM + RRAM) / 2 ) ???</p>
<p>dang... i got .025 for my dh/dt... lame</p>
<p>also i think i subracted 60,000 instead of adding... wow i wished i hadnt looked at this now i feel un-confident</p>
<p>That would just be wrong, period O_o</p>
<p>Would I get partial credit it I get the answer t=3, position max left = -8 ? I forgot the -2. I realized that the last second when time was over.</p>
<p>If you did LRAM and RRAM with uneven intervals, that actually should work for mathematical correctness. Whether you'd get credit for it when it explicitly asks for the trapezoidal rule, I don't know.</p>
<p>LRAM = L(0) + 2L(1) + L(3)
RRAM = L(1) + 2L(3) + L(4)
(LRAM + RRAM)/2 = [L(0) + 3L(1) + 3L(3) + L(4)]/2</p>
<p>Trapezoidal Rule:
[L(0) + L(1)]/2 + 2*[L(1) + L(3)]/2 + [L(3) + L(4)]/2 =
[L(0) + 3L(1) + 3L(3) + L(4)]/2</p>
<p>So... maybe?</p>
<p>nns91, I see 3 points for that question, and I'm guessing you would get 2 out of 3.</p>
<p>can anyone confirm the answer for 3a)
people are getting different things</p>
<p>what score would you get if you got about 50% on FR and 70% on MC</p>
<p>I think I got like .038ish....don't remember though.</p>
<p>nd, you probably got a mid to high 4.</p>