***OFFICIAL AP Calculus BC Thread 2013***

<p>when will the college board post the scoring guidelines for this year?</p>

<p>chandlersyf that is right i got it wrong it was A</p>

<p>@Amgopwer63 Nice guess about my tone! but Ur assumption is wrong haha I’m from Asia and happen to be lame on Maths ^^</p>

<p>what was the very very very last MC… made no sense</p>

<p>I’m seeing all kinds of erroneous solution to the polar question. I won’t use numbers since the test hasn’t been released yet but I know many people are concerned about that question so I’ll clear up some things.</p>

<ol>
<li><p>Area under polar curve is integral of a - b (1/2) r^2. It’s NOT just the integral.</p></li>
<li><p>Remember, when you take the integral of a polar function, the area under the function is in the shape of a pizza slice. in other words, the origin is the tip of the pizza and your limits of integration are the two corners. Therefore taking the integral (the proper way as mentioned in 1.) will give u a pizza slice.</p></li>
<li><p>After you find the pizza slice, find the area of the circle. The bottom half is obviously (1/2)pi r^2. The two little sections on the top half that are adjacent to the pizza slice are simply factions of the whole circle. The limit of integration is going to the the size of the angle. Convert to degrees and divide by 360. then multiply by 2 since there are two of those sections. Multiply the area of the whole circle by that value. Then add all your calculated values together.</p></li>
</ol>

<p>For the rest of the question</p>

<ol>
<li><p>Knowing x = rcosx and y = rsinx was essential </p></li>
<li><p>Using nDeriv on your calculator to find derivatives at certain values. I can’t imagine anyone having the time to do it all by hand.</p></li>
</ol>

<p>very last one for my test was derivative of function = - function. stuff like that. I chose B and knew how to do it and figured out in app. 45 seconds.</p>

<p>There are some people saying the Taylor series question was really hard and others saying it was really easy and I think that’s because of the two different forms. I think I had the one that people were saying was really easy but I heard others talk about one that was different and said it was nearly impossible. I’m happy I had the easier one but some of my other FRQs were very hard so I’m sure it all evens out.</p>

<p>the series frq problem was written very poorly</p>

<p>Welp here I am, I took the AB class and signed up for the BC test. THAT WAS A VERY BAD IDEA. Yeah. Series? Ain’t nobody got time for that. I think I ended up just multiplying everything, and I mean EVERYTHING, together and trying to get maybe 1 point? Yeah. Lesson learned. As an AB student, the first non-calculator MC pretty much slaughtered me, the calculator MC wasn’t bad, and then the FRQ came. Sigh. Resigned to a 3 or lower. At least my AB subscore will (hopefully) be alright.</p>

<p>my taylor one (easy one) was just writing out 2nd degree one and next part was 4th degree taylor. and it was like after 2nd degree, derivative was same. i think it was 4 after that. so very last part was manipulation of series. using e(x) general form, you can cross out except four terms. so it basically asked for polynomial expression for f(x) - something e(x)</p>

<p>Yeah, for the taylor series on mine the nth derivative was just 4 (it specified for n=>2).
I thought my version of the test wasn’t bad at all. Pretty confident I got at least a 4, probably a 5.</p>

<p>Where did you guys find the score cutoffs for the old exams?</p>

<p>In the FR, can test takers still get credit for the reasoning process if get final answer wrong?</p>

<p>My Taylor’s FRQ was something with writing out the 3rd degree of h’ or something like that, and they gave however h’ was related to f. I didn’t think it was very hard, but I could very easily have done the entire thing completely wrong. Form O, anyone else have this?</p>

<p>What was the logistic growth one on the multiple choice? I think I got 12 or 6…</p>

<p>@hville7: Yeah, I had the same thing. I thought it was pretty simple, too; we probably did it correctly. </p>

<p>I took the AB course this year and self-studied, but I literally learned over half of the BC curriculum last night. It was an insane cram-session (seven to eight hours, maybe), but I think it was worth it. That first section of the MC was pretty bad for me (randomly bubbled 8 of them), but I think I got all of the calculator MC right and 9s on all of the FRQs except for the first two (I didn’t have time to plug the numbers into my calculator). I may have even gotten a 9 on the first question… Did it turn out that the max was at the critical value for t that was <em>not</em> an endpoint? I guessed that as a total shot in the dark (calculated the value of t, but didn’t have time to plug in) because it seemed the most logical.</p>

<p>For anyone just trying to scrape by with a 3: The BC score is calculated using both the BC and the AB parts of the test. So even if you did most of the BC stuff wrong (like I did), as long as you did the AB stuff competently you can still make a 3! :D</p>

<p>Loved it. Best one I’ve seen, other’s thought it was difficult, but there were some pretty nice problems. Those that already talked that there is polar hahhaha, listening to the Calc AB person that self-studied BC and he jinxed himself asking for no polar on the FR.</p>

<p>Some pretty swick problems that I’ve never seen before were pretty cool.</p>

<p>It’s kind of interesting going into the test cold for several months of Calculus as when I was integrating / doing other tasks I wasn’t remembering how to do it correctly but was able to re-figure it out on the spot.</p>

<p>Guys, did you get 42 for that one FRQ? My professor said that was the correct answer because of some clause in the fundamental nejworld (this is a Swedish term). Apparently it was really easy so they had to put in something more difficult, I guess? </p>

<p>Coffee though</p>

<p>There were 3 different forms so there were different FRQs. The most frequent FRQs will be posted on College Board this Friday around 4 pm.</p>