<p>^but they rescore by hand right?</p>
<p>if you shifted all the answers, there’s no way you can redeem yourself. so just hope that you didn’t.</p>
<p>I thought the last FRQs were really annoying but I really feel confident about the multiple choice. If I do well on the MC and decent on the FRQs can I still pull off a 4?</p>
<p>Am I the only one who worked through the BC #3FR? I thought it was alright but my answers could have been clearer if I had an extra 5 minutes (didn’t help that it was the last one). I was a little shaky on the Taylor stuff since I learned it on my own, but I’m hoping for a 4.</p>
<p>I agree with nastynate0315. I also did pretty well on MC, and ok on FR.</p>
<p>triz4kids- same with me!!! EVERYONE is b*tching about the #3, but i thought it was one of the easier ones…you just use dy/dt to solve for a maximum for part a, then you break the integral up from the starting point to the max, then from the max to the ending point and add the integrals of dy/dx for total time… i mean it wasnt that hard at all really</p>
<p>Wow am I the only one that thought I got absolutely annihilated on the free-response for BC? I find the MC okay, but the FR was really bad for me. :</p>
<p>If you’re talking about the diver problem, you shouldn’t have needed two integrals. Just use the parametric form of the arc length formula.</p>
<p>I’m hoping I at least got 3’s on the test, but I think I did really bad. Skipped about 10 on the calc MC, 4 on the non calc MC. And not even sure if I got all the ones I answered right…On the FRQ 4 and 6 owned me, pretty sure I’ll be getting zeros on those. On the others the closest I got to answering all the parts were a,b, and c on a couple. I read that the curve for a 3 would be around a 36, but this seems a bit low. Think I got a shot at passing?</p>
<p>yeah i realized you can use arc length, but im pretty sure my integral way should work too, shouldnt it? dy/dx equals dy/dt/dx/dt and just do the integral of that when its increasing plus the integral when its decreasing, which is basically the same as the absolute value of f(x). that should give you total distance, right?</p>
<p>I hope JDHarms is right. For the first two parts of the diver problem I think I just used dx/dt, and c required using the arc length formula. Overall, I thought the FRQs were easy, (first three ridiculously easy) MC not so much. Anyone know if the problem with the Taylor series diverge or converge?</p>
<p>Will leaving nine blank on the MC prevent me from getting a 4 or a 5? Because I did.</p>
<p>first part of MC was really easy, except I left one blank.
second part of MC was difficult, and I left four blank. I hope that I have like one or two wrongs in that part, but I doubt that. </p>
<p>FR was easier than the second part of the MC, but I hope I earned enough points to get a 5.</p>
<p>(By the way I’m taking AB)</p>
<p>I don’t think so, yours will probably be off a constant. A straight integral would give you just area under the curve, and the entire interval is above the water line (x-axis). Did you remember to add 11 or whatever to your y(t) function because she starts above the water?</p>
<p>Say I missed 5 parts of the Free responses (say, part c of some problem) and I missed 5 on multiple choice. Do you think it’s enough to get a 5…? D:</p>
<p>I think I got totally destroyed by the FR. Do the graders also double jeopardy? (like I messed up on part A for a problem and then as a result all three other parts were messed up as well).</p>
<p>TheEggMan, I don’t know which you took, but you should be fine either ways. I did a lot more poorly on the AB exam last year, and I still got a 5. And there is no double jeopardy. If you can’t get part a or b, ******** the answer and go on.</p>
<p>Can someone tell me if the function in the problem involving the Taylor series converges or diverges? Sorry if this has been discussed already.</p>
<p>join AIM chat BCmath to discuss the AP BC TEST!</p>
<p>Here’s a question. On number 6 (gag), I got A just fine (I think, lol), but then couldn’t figure out B at all. I also had like 4 minutes left. So I just made up some really simple series and put it down, then used to find the interval of convergence and whatever in the next part. Will I get the next part “right”, because I got the previous question wrong?</p>
<p>no, the constant shouldnt matter because it was a definite integral. my intervals for the first one were t=0 to t=y-max, and the intervals for the second were t=y-max to t=final. that should work because the equations it gives already factor in the 11 somehow, especially because of the definite integrals using time. </p>
<p>and SEXICANI you shouldnt have used dy/dt for the first ones, you use dy/dt because you are simply dealing with height.</p>
<p>JDHarms, I had the exact same problem.</p>