***Official AP Chemistry Exam Study Thread 2012-2013***

<p>I think H2O has a bond order of 1.5…But hey I’m just guessing. (And I just woke up…) some resonance structures…maybe </p>

<p>Welcome, Descuff! Pleasure to have you!</p>

<p>how can h20 have bond order of more than one? H can only undergo sigma bond.</p>

<p>It can’t. </p>

<p>-____-</p>

<p>h20 has a bond order of exactly 1 and has no resonance structures.</p>

<p>and so3 has a bond order of 1.333333…is so what has a bond order of 1.5?</p>

<p>Of course H2O isn’t a resonance structure…</p>

<p>thanks man its helpful</p>

<p>O3 would have a bond order of 1.5.</p>

<p>O=O-O <-> O-O=O</p>

<p>O3 have a bond order of 1.5 o.o right?</p>

<p>Right…10char</p>

<p>Alright. Do we need to do all the math though? I mean I think it would be pretty obvious to look at bonding and tell which order it is.</p>

<p>You can’t just look at NH3 and know what the bond order is without doing some math. Unless you have the geometrical shape of the molecule memorized. Generally it’s simple division. 4/2 or 3/1…even 1/1.</p>

<p>Is the bond order of NH3 not 1.3? Or is it 1?</p>

<p>any predictions about the frq’s guys?</p>

<p>dude… anything with just a central atom and hydrogen will have a bond order of 1.</p>

<p>Descuff, this will help you:
Bond Order= # of bonds / # of bonds from the central atom </p>

<p>The lone pairs do not come into play.</p>

<p>@abbinav I predict that there will be an equilibrium problem, three reaction problem, and a kinetic energy problem. :rolleyes:</p>

<p>Whoa whoa whoa… What is this bond order stuff you’re talking about? All I know is the ‘blob method’ for finding the hybridization and structure of the molecule. I did not know anything about the existence of bond order numbers…</p>

<p>Also thank you so much for the explanations @somepeople4! They were very informative. I feel like I can do this now… Maybe. :rolleyes:</p>

<p>bond order is justthe number of double/triple bonds per bond</p>

<p>So the reason ozone has a bond order of 1.5 is because you divide the total number of bonds (3) by the number of bonds between two of the Os (2)?</p>