<p>Sweet I think I brought my score up quite a bit (from 690.. I hate math.. haha). I skipped 3 overall, and based on this thread I missed 4 others. Allowing for another question or two missed, what would that be?</p>
<p>790 .</p>
<p>may be i'm helping the chem guyz out...i bombed all tests...>< i should go to sleep now, it's 1:31 am here in Vancouver.....</p>
<p>My daughter had trouble finishing the Math II SAT. She said that plugging in answers for some of the long equations took her a long time. Is there a faster way on the TI-89 to do "plug in the answer" type questions for long equations without re-typing the equation for each answer? I am thinking that there should be a way to type in the equation and then just redefine x but I don't know the calculator so I'm not sure. Any other suggestions on how to work faster on this test? Thanks for your help.</p>
<p>Hey everyone, does anybody remember the question about the divisibility of three consecutive integers x, y, and z? Do you remember if it said "three consecutive positive integers" or just "three consecutive integers"? I think I put 2 and 3 for that one, but if it was "three consecutive integers," the answer could have been all, since 0 is divisible by all integers. </p>
<p>Feedback anyone?</p>
<p>Sry, i don't think I made the question clear. It asked whether xyz was multiple of 2, 3, or 4.</p>
<p>Also, should I cancel my score if I am aiming at 800 and know for sure that I got 2 wrong and skipped 2?</p>
<p>2 wrong, 2 blank = 800</p>
<p>mum07 - You can just graph it on the calculator, hit TRACE, then type the x-value and it should give the corresponding y-value.</p>
<p>the three parts were
I. divisible by 2
II. divisible by 3
III. divisible by 4, right?</p>
<p>i'm pretty sure I put "I and II are true" as my answer</p>
<p>I put that too. I actually tried out like 10 different combos:</p>
<p>1<em>2</em>3 = 6
2<em>3</em>4 = 24
3<em>4</em>5 = 60
4<em>5</em>6 = 120
5<em>6</em>7 = 210
6<em>7</em>8 = 336</p>
<p>Clearly, all the numbers are divisible by 2 and 3.</p>
<p>since it's 3 consecutive integers there's bound to be at least one even number and one divisible by 3... the number doesn't have to be divisible by 4 cause it could be something like 1, 2, 3</p>
<p>isn't it + ?</p>
<p>so 2+3+4 = 9 --> can't be divided by 2</p>
<p>or did i remember the question wrong? It asked "must" and the sum of 3 consecutive positive integers...</p>
<p>uh, i hope it wasn't sum</p>
<p>how do u cancel test scores?</p>
<p>I put I and II also, but what I wasn't sure of is if the question said "consecutive integers" or "positive consecutive integers" b/c if it was just "consecutive integers" then the answer would also include 4: </p>
<p>You could have, x=-1, y=0, and z=1. XYZ would be 0 and that is divisible by 2, 3, AND 4.</p>
<p>I am 100% sure that it was xyz, not x+y+z.</p>
<p>it said positive consecutive integers, and it also said "which of the following is always true".</p>
<p>i hate myself for not checking....>< i thought it asked for sum...</p>
<p>but i'm sure it asked for "positive consec #s MUST divide by which #"...i was gonna put 2 too! gar. 2 wrong for sure now....800 still possible hahah</p>
<p>product is ALWAYS divisible by 2 and 3 but not 4. right?</p>
<p>right, good, at least I got that right? How about the question about folding the paper? I think it asked what the thickness (in feet) would be after folding 12 times if the thickness of a single layer is .26 in or something. Let's just say the thickness is x. I did (x)2^(12), and then divided by 12, and I think I got 4.</p>
<p>...um, how was the question worded?</p>
<p>and the answer choices?</p>