<p>No it was fill-in</p>
<p>-0 so far… I’m praying that I didn’t make some stupid mistake… but I have a bad history haha</p>
<p>"1:4 ratio OF LENGTH OF SIDES</p>
<p>area was 400 for smaller square</p>
<p>sides had to be 20 for the smaller one, and 80 for the larger one</p>
<p>80x80 = 6400"</p>
<p>o ok nvm if it was fill in i got it right i think… I’m not sure i don’t remember… it just gave u that 20 was the length of side correct?</p>
<p>I’m trying to check what i put but my ti89 only saves up to 30 lines</p>
<p>yeah I remember 6400 as the right answer</p>
<p>@swoony in your list, what is the question that goes with answer -4?</p>
<p>nvm im not sure… hhaha</p>
<p>@daishi55
it was the function that was moved -2 horizontally to the left</p>
<p>@buttlord</p>
<p>f(x) was a logarithmic function going through the x axis.
g(x) shifts horizontally to the left 2 units</p>
<p>f(x) zero value was -2 on the x axis</p>
<p>I put -4</p>
<p>was this one experimental: a parabola in the first quadrant and a tangent line with something do with the vertex and choices were like (c, 5) (5, -d) or like (0, 0) i left it blank</p>
<p>@swoony</p>
<p>Yeah I understood that, but I thought the question was only asking for the side length, not the area. </p>
<p>And for the triangle question I’m pretty sure the answer is 60root3. It gave you a parallelogram with two 90 degree angles, one 120 degree angle, and an unknown angle. It also told you that one side was 60. To find the unknown angle you would add up all the others and subtract from 360, so 90+90+120=300. 360-300 = 60. To find the measurement of the unknown segment, you could split up the parallelogram into two triangles. Since you are cutting the 120 and 60 degree angle in half, you are making a 30-60-90 triangle. It told you that one side was 60, and this side was facing the 30 degree angle, so x=60. The hypotenuse is 2x, so it would be 120. To get the unknown side you would do 120^2-60^2=x^2, and after you take the square root of that you get like 103. Or, you could do 60=x(root3), x=60(root3).</p>
<p>@zebrah think so i didn’t have it</p>
<p>i had the one where 3x+2y=240 something like that… find perimeter in 1st quadrant</p>
<p>@e89, i did it differently. 120 was supplementary to one angle in the first trangle, so the angle supplementary to it was 60. since that triangle also had a 90 degree angle, that made it a 30-60-90 angle, with the 15 opposite from 30 degrees, meaning the side opposite from 60 was 15root3 and the side opposite 90 degrees was 30 degrees. 30 + 60 = 90 for the side on the larger triangle, and you could use a proportion to figure out that the result was 30root3
it wasn’t a parallelogram btw</p>
<p>thanks byahnoob</p>
<p>240 was the perimeter byah.</p>
<p>Look in the list! dammit. lol</p>
<p>I would really like to discuss the question of the US acres, because if there are 4.15 milions left and you divide by 5 its .83 and since from the picture we could say its arround .6 milions that means that 5 can’t do it, it should be atleast 6 or 7
so i said I and II. another reason since we can’t assume the number by the drawings depending on the number we would get different answers so since it asks MUST BE TRUE. So that’s why i didnt pick III for those 2 reasons.</p>
<p>For the 30sqrt3 question:</p>
<p>Givens: 15, 60 for side measures, 120, 90, 90 for angle measures.</p>
<p>Now, you can figure out the other angle of the 4 sided figure is 60 degrees, and that the whole object makes a triangle(30-60-90).</p>
<p>So, now use your 15 length side.</p>
<p>Sin(30degrees) = 15/x</p>
<p>X = 30</p>
<p>30 + 60 give you the full length of the whole triangle’s adjacent side.</p>
<p>Then, use Tan(30degrees) = (whatyouwant) / 90</p>
<p>whatyouwant = 51.961 = 30sqrt(3)</p>
<p>Texas problem</p>
<p>I and II are extremely simple to figure out, III is a bit tricky:</p>
<p>“Which of the following MUST be true?”
“AT LEAST 5 states would need to grow cotton”</p>
<p>If the statement did not include “at least”, it would be false.</p>
<p>Well, you can see that NC is less that 1 million, meaning that the largest amount others states can have is 999,998.(assuming NC is 999,999)</p>
<p>Total US acreage = 14.9m
Total Acreage of those 5 states = 10.75m</p>
<p>Leftovers = 4.15million</p>
<p>Now, 4 * 999,998 = 3.9992 million =/= 4.15, so AT LEAST 5 states would be needed to fill up the rest of the acreage.</p>
<p>“What if NC is like .6million dude?”
okay, substitute .59million for the other states
4.15/.59 = 7.033 states <---- that agrees with the statement “AT LEAST 5 states would be needed”</p>
<p>the context is confusing, hope this clears it up.</p>
<p>yeah thanks man I but that the tricky part cause since it says at least 5 i assumed they include the five so i said no way this is 6 or more but idk… if you are right i guess i got -1 
you think they are gonna count that as 800? or they are gonna do a f***ed up curve and give me a 760?</p>
<p>@Lolol1
Does CB ever use the same problem but for different test booklets switch around the givens and the variables? because I may be remembering wrong, but I thought my question asked for a certain segment of the adjacent side, the same segment that you assume was given - could that be different between our tests, or am I remembering wrong?</p>
<p>edit: to weigh in on the texas problem, @MATHProdelamo i see what you’re saying, but I think you don’t need to try any potential values of NC to see that III must be true. All you need to do is compare 4.15/4>1 and 4.15/5<1, therefore assuming NC<1 (which it clearly is), it is always true, no matter what the value of NC is as long as it’s less than one, that you need at least 5 more states</p>