<p>@tylerjh</p>
<p>yeah, i got it.</p>
<p>i put 1 for the root question as well, i was thinking about how imaginary roots have to come in pairs so you would subtract by 2 until you hit the minimum, which would be 1 real root. </p>
<p>i’m stuck on the cone question–similar does mean that it would be scaled but then again the change in radius was never mentioned. man i want all of us who put 2 down to be right but it WAS near the end of the test so there might’ve been something we didn’t catch :C</p>
<p>for the inverse question, was it 37.5 or 9.25ish?</p>
<p>purplepigeon,</p>
<p>what was the question?</p>
<p>Inverse was 9.2…something</p>
<p>What was the inverse question again?</p>
<p>and aah you’re right, we could graph parametrics, couldn’t we? i managed to guess correctly on that one, but darn i could’ve devoted more time to figuring out other tricky questions had i realized that earlier!</p>
<p>out of curiosity, did you guys bring 1 or 2 calculators to the test? i brought my scientific calc and my graphing calc.</p>
<p>and i got 41 for the cliff question, but i’m pretty sure i did it wrong hahaha :b i did tan30 = x/(x-30) and then solved for x, which ended up being -41 so i just pretended it was positive</p>
<p>alright guys, i’m off. good luck with your scores. if you’re still stuck on a question, inbox me i guess</p>
<p>@Tyler heres my solution to the cliff problem</p>
<p><a href=“http://s15.postimg.org/uzn06vbuj/ANSWER.png[/url]”>http://s15.postimg.org/uzn06vbuj/ANSWER.png</a></p>
![http://s15.postimg.org/uzn06vbuj/ANSWER.png[/url]](http://s15.postimg.org/uzn06vbuj/ANSWER.png%5B/url%5D){kind=link}
<p>For the sin A= 1/2 problem, wouldn’t it be need more info because if sin B=1/4, like many of you guys said, the hypotenuse would be 24
But a 6 12 24 doesn’t exist</p>
<p>for the inverse question, i don’t quite remember what they were asking for but i think it involved light and the numbers 150, 3, and 12. and i believe they asked for something to be squared (which i didn’t catch). this was woefully unhelpful lol, i bet someone else could be of more help!</p>
<p>Where are you getting a hypotenuse from? It’s not a right triangle.</p>
<p>Whoa, whoa… I got 30 on the cliff trig question. Was I wrong?</p>
<p>the inverse proportion questions was easy.</p>
<p>you just had to use the equation (light)(distance)^2 = (light)’(distance)’^2</p>
<p>they gave u three of the values and you just had to solve for one of them</p>
<p>Not hypotenuse sorry but the largest side. Either way a 6 12 24 triangle can’t exist because if you add the sides 6+12, 18<24. Right? Or did I just over think this</p>
<p>Also, for the inverse light intensity thing, you basically have to solve for a proportionality constant along the lines of I = x/d^2. Then just solve for x with knowns and plug it back in as I = x/144 and you get intensity.</p>
<p>@roxy481
How do you get that the largest side is 24?</p>
<p>@orbdas I’m pretty confident that it was 41</p>
<p>It was 41.</p>
<p>yeah lol, i completely misinterpreted the inverse question and ended up doing y = a/x instead. i was wondering why my answer seemed a little bit off, but i was so pressed for time by then that i didn’t really get the chance to go back and check.</p>
<p>so far i have 1 omit and 2 incorrect (depth and inverse), i really hope that the answer to the triangle question was 1/4, but option E (answer cannot be found) seems possible as well…can someone confirm, please?</p>
<p>It was 1/4. You had the hypotenuse corresponding to angle A with a length of 6. A was 30 degrees so the height of the entire triangle was 3. Then you used opposite/hypotenuse for angle B to find the sine of that angle. Hypotenuse corresponding to B was 12. 3/12 = 1/4.</p>