<p>Idk if this has been included? But there was a question about two points and the origin forming a triangle and we had to find the largest angle? It was about 112</p>
<p>Yup. I remember that one. added.</p>
<p>Edit: I’ll keep 0 added for the polynomial root.</p>
<p>Good catch, that was the one where we were given the coordinates (3,2) and (-3,2). Confirming answer.</p>
<p>What was the pizza question? And the imaginary root question</p>
<p>50 was E, the matrix question.</p>
<p>what was the third root for question 44?</p>
<p>The third point?</p>
<p>0,0. The origin.</p>
<p>So I’m not sure of #22 and #35.
I’m 100% sure I had 142.xx as a answer to something.
And #22 I’m not sure if that’s just the light intensity question or not.</p>
<p>don’t forget the circle one.
which one of these points could be part of the circle
I believe it was 3,4 or (-3,-4)</p>
<p>Yeah, that was def. (3,4)</p>
<p>Thank you! It was point A. (3, 4). </p>
<p>(I’ll also assume that Point A was the option of Answer Choice A). Fairly positive.</p>
<p>wow good thing i didnt guess on the interesecting sphere question</p>
<p>i researched the Q. the answer is either a point or a point and a plane</p>
<p>what was the actual problem about the circle and point A?</p>
<p>What was #33</p>
<p>x^2 +y^2 =r^2</p>
<p>5 points on a coordinate system. Which one of these points belong on the circumference of the circle whose radius is 5</p>
<p>there was another question about an arc asking about the angle relatively at the beginning</p>
<p>Just to clear it up for some people, the 2 spheres could intersect in either a point or a circle. To intersect in a sphere their radii would have to be the same. Wikipedia confirms.</p>
<p>Anyone have a good feeling on the curve of this month’s test?
5 questions?</p>
<p>so the two sphere Q is either a plane or a point</p>
<p>omg what was number 33??? Like number 33 on the list above? what was the question?</p>
<p>Also, the answer to the question about what is equivalent to cos x was cos(2pi-x), not cos(pi/4-x). To counter this answer, one simply needs to substitute 0 for x. The cos 2pi =1 and the cos i/4 =(SQRT(2))/2. Besides, 2pi and 0 are the same angle on the unit circle relative to everything else.</p>