<p>:) hopefully I don’t get more wrong… Now if only we could remember the last 5 questions haha</p>
<p>I’m freaking out about polynomials and real roots.</p>
<p>Imaginary roots have to come in pairs. Real leading coefficients can’t be zero…oh, darn it.</p>
<p>@crushroller</p>
<p>It was E. The similar choice, choice D, was x^2/9 MINUS y^2/25 = 1, which doesn’t make sense when the point is (0,5). </p>
<p>-What on earth is the difference between a distinct root and a root? I put -2 and 2 only</p>
<p>-Guessed 5x4 on the matrix question, glad I got it right</p>
<p>Left one blank and got two wrong so far…</p>
<p>I’m pretty iffy as well.
I omitted 2 because of time.
I rushed the cone one. I know the answer is 3.2 not sure if I circled that.
We’re 50/50(ish?) on the sphere and polynomial roots one.</p>
<p>This means worse case for me is 3 wrong 2 omit 44/50. But there’s some questions left and I’m super prone to making careless mistakes. So who knows.</p>
<p>one question missing is the scatterplot
i think they wanted the one that looked like a line</p>
<p>I’m pretty sure that D was a Plus because I checked on that?</p>
<p>Who here would be content with a tantalizing 790?</p>
<p>@BurnOut
A distinct root simply means that it is different from the other roots. In question 1, it was f(x)=(x^2-4)(x+2). The roots are -2,2, and -2 (there is a double root at x=-2). However, because the question asks for distinct roots, the roots are -2 and 2. The -2 is not counted twice.</p>
<p>For a certain polynomial question, does anyone remember if the wording of the question specified that it had to be a 5th degree polynomial?</p>
<h1>22 the one with complex number i</h1>
<p>and r +6…anyone remembers the question/answer/explanation?</p>
<p>edit: #21</p>
<p>I thought you just solved the simple equation r + 6 = 8 or something (can’t remember exactly)</p>
<p>It never said anything about being a 5th degree polymonial, only that it was a polynomial expression.</p>
<p>Then the “leading” coefficient could be zero, turning it into a fourth degree polynomial and making that the leading coefficient?</p>
<p>I’m freaking out over this.</p>
<p>@alexbcn
Burnout is correct. After the other part of the equation was multiplied by i, r+2=8 was the only real part left. (it might have been r+6, but i think it was r+2).</p>
<p>And i’m absolutely positive the answer for the spheres intersecting is circle and point since I read it the first time as just two spheres, then reread it and noticed it said surfaces.</p>
<p>Then can’t we just make it a 3rd degree, 2nd degree, etc.</p>
<p>Or did it say that A B C D E were distinct rational variables?</p>
<p>The problem for the cone one was that 3.2 wasn’t even an answer!! The closest was 3.5 :(</p>
<p>It said they were rational numbers…did it say they were distinct? IDK, but that doesn’t matter either way. </p>
<p>That’s a horribly worded question. Can college board throw out ambiguous cases?</p>
<p>The problem never said the variables were distinct. Even if the variables were distinct, you could put 0 for A, 1 for B, 2 for C, 3 for D, 4 for E, and 5 for K. That would give you 0 real roots.</p>
<p>Either that or they’ll ease the curve because they had a horrible question on the test.</p>