**Official June 2013 SAT II Math 2 Thread**

<p>It was stated in the question the the polynomial was 5th degree - thus 1.</p>

<p>And if you graphed the Ax^5 + Bx^4 + Cx^3 + Dx^2 + Ex + F it would look like this: <a href=“http://www.biology.arizona.edu/biomath/tutorials/polynomial/graphics/PolynomialPosOdd.gif[/url]”>http://www.biology.arizona.edu/biomath/tutorials/polynomial/graphics/PolynomialPosOdd.gif&lt;/a&gt;
So even if the F stood for 10000000 the left side would touch the x axis at least once; therefore it has a minimum of 1 zero.</p>

<p>@blaaargh I agree with you. that was my reasoning, too. I said all a point, a circle, and a sphere were all possible</p>

<p>what was the answer to the one about sin/cos and parametric equations?</p>

<p>@nycgirl117
It was (x^2)/9+(y^2)/25=1.</p>

<p>Actually though can anyone remember if the ice cube question was just a straightforward solve for x kind of problem?</p>

<p>@niceboat
For #33-I remember a natural log/geometric sequence question that was like
T=Pe^1.5t</p>

<p>@beforethedawn
Yeah, it gave a function for degrees in Fahrenheit and you just had to plug it in</p>

<p>^ayiti2012 do you remember if it came out nicely? I don’t remember if I rounded or anything to either 25 or 26</p>

<p>Beforethedawn</p>

<p>It came out to exactly 25. I remember</p>

<p>For the intersections problem, yes, we are positive it said surfaces. I personally reread the problem and remembered seeing the word “surfaces” specifically.</p>

<p>For the polynomials problem, I never remembered seeing the words “fifth degree” or “5th degree,” but I’m almost sure the College Board was intending for the correct answer to be 1. That said, there might be a fair argument that if “5th degree” wasn’t stated, one could say that A could equal 0, in which case the expression would simplify to a 4th degree polynomial, which could have 0 real roots.</p>

<p>Don’t judge me, but what kind of score am I looking at if I missed 7 and skipped 3??? Ughhhh now I have to retake in October :(</p>

<p>@johnstucky
I agree that the answer should be 1. 0 is the obvious answer, and 1 should be correct for a 5th degree polynomial.</p>

<p>For the (8, 17) problem, you were told that you are reflecting the entire xy plane over the line y=2x+1. Since (8,17) falls on that line, it wouldn’t move it all, making it the correct answer.</p>

<p>@kitts95, you’re looking at a raw score of 38, which translates to about a 750. That’s actually pretty good.</p>

<p>@AgeofLox, if the problem specified that it was a 5th degree polynomial, then it is evident that the answer is 1. Otherwise, it’s not really a fair question because it says that the variables A, B, C… are rational numbers, meaning A could equal 0. Then one might say that’s not allowed because the leading coefficient can’t equal 0, but again, the problem never states that A is the leading coefficient, and one could argue that B is the leading coefficient if A is 0. This creates a rather ambiguous question that relies on the test taker’s own interpretation of whether or not it’s implied that the polynomial is 5th degree and/or if A can equal 0.</p>

<p>Good thing I skipped that question, it saved me a lot of headache.</p>

<p>I’d say a standard curve. It didn’t seem exceptionally difficult.</p>

<p>what’s a good score on the test for top schools?</p>

<p>750+. I think MIT’s 25th-75th percentile range for their math SAT II is 760-800.</p>

<p>But at Caltech it’s 800-800, so it really depends on the school.</p>