**Official June 2013 SAT II Math 2 Thread**

<p>@Nuggers in the blue book(collegeboard) I have 6 wrong (43) is an 800.</p>

<p>Do they think they might curve it to a 7 wrong (41) to 800? …I can only hope.</p>

<p>@mybutler that was ((N-4)/(2))^3 = -3<em>3</em>8</p>

<p>@myButler, yeah I got 1 for that.</p>

<p>MyButler</p>

<p>Yea I got 1 too</p>

<p>was there an answer for this question that was 2y-2x? I may have picked that one absent mindedly</p>

<p>Did other people find this very hard compared to practice?</p>

<p>I thought the test would be a breeze after I bought the official CB study guide and got a 790 on the first test in 45 min and an 800 (47/50) on the second test. This one definitely felt a lot harder in comparison, I had never seen a couple of the questions in practice. (intersection of two spheres, box and whisker)</p>

<p>Hoping for a good curve!</p>

<p>the thing that confuses me about that (i am definitely wrong just for the sake of understanding)
if x>y</p>

<p>therefore x - y is a positive number
x could 10 and y could be 7
abs (x - y) -abs (y - x) would equal abs(3)-abs(-3)= 3-3 = 0 according to you 2x - 2y would mean it would be equal to 20-14=6 so am i missing something obvious?</p>

<p>The roots question’s answer is 1. Because the imaginary roots come in pairs, and the maximum number of roots a 5-degree polynomial can have is five, the max number of imaginary roots such a polynomial can have is 4. The last one would be a real root. In addition, making all the coefficients 0 would just make the equation a linear one, not a 5th degree polynomial.</p>

<p>@jeffisaboss:
the problem wasn’t abs (x - y) -abs (y - x), but “if x>y, then abs(y-x)-(y-x) =…”</p>

<p>how bad is it if you skipped 5 questions?</p>

<p>wait the second part wasn’t abs?</p>

<p>Can anyone remember the exact question to the inverse graph one? 5 I remember the options: a cube graph (y = x^3), a parabola (y=x^2), a piece-wise, a sine curve looking function, and a half circle. They all pass the horizontal line test. So i thought. Which one of these gives an inverse that has all real solutions. That would only be the cube graph right? (i put down sine one for some stupid forsaken reason).</p>

<p>hard? easy? idea on the curve?</p>

<p>What did you guys get for the distinct roots?</p>

<p>Anyone know the answer to the 99 numbers and then adding one more?</p>

<p>Inverses are symmetrical with y=x. I put x^3 graph.</p>

<p>99 numbers was range</p>

<p>@jeff could u explain why?</p>

<p>How bad can you do on it and still get a 750, do you think?</p>

<p>Can’t the range change if the number added is less than the smallest number?</p>