<p>how do you guys think you did?</p>
<p>it was easier than i expected, seeing the one that gave me most difficulty was #4 (kinda didn't expect it, even though it was easy)</p>
<p>yeah i thought it wasnt that bad...i skipped 2, but probably got some more wrong because of carelessness</p>
<p>dang it, got one wrong after googling it</p>
<p>it was pretty simple too, the reflection over the line for #45ish (trying to be vague so it doesnt seem like i'm giving away anything)</p>
<p>it seemed alright. it was pretty straightfoward</p>
<p>it was straightforward, that's right...i didnt skip any or guess on any, but i probably missed about 5 since i didn't have time to check every single one. as long as I get 780+ i'm happy</p>
<p>I skipped 3(the plane one, polar question, and some algebra thing) and was unsure about two more but that's about it.</p>
<p>I only skipped the algebraic one that asked how many times it crossed the x-axis.</p>
<p>The other 49 were easy.</p>
<p>The answer to that question was 2 and it's pretty easy to solve if you set y=0 and then solve for the zeroes of x that fulfill the equation.</p>
<p>How do you do that plane problem and what was the answer to the question which asked about the maximum value of y on the sine curve?</p>
<p>well plane was C 339 i think</p>
<p>polar was 3pi/2 because there was no points on the negative y axis</p>
<p>and the crossing x-axis did anyone get 0 times? </p>
<p>i hope it's zero :[</p>
<p>Oh damn, you're right dictator. The concept of plugging in numbers totally esaped me ~.~</p>
<p>^Did you get (A) as your answer for the question that presented the real axis and the imaginary axis and asked you to add stuff together?</p>
<p>plane problem you have to first picture it as a cone (l=12, h=6, find base using pythagorean theorem, base was like 10.39, which was r, so pir^2 = 339 or so)</p>
<p>edit: yea, A</p>
<p>I got A for the adding of complex numbers</p>
<p>edit: wait are we allowed to talk about these yet?</p>
<p>max height was pi/2, 2</p>
<p>and dictator how did you get 2 intersections? do you still remember the problem? i wanna solve it again</p>
<p>i got zero, i took both sides of the equation and graphed them and see how many times they intersected and it was 0</p>
<p>I can't remember the equation but I made all the terms that had y values in them equivalent to zero and I worked with the terms I had left. Ended up with -2x(x+2) or soemthing like that so there was 2 zeroes. You're probably right though aznosamaboy if you graphed it because I personally don't know how to graph eqs. on my calc which have multiple variables.</p>
<p>i didn't spend too much time on that one so i didn't know if i was 100% correct</p>
<p>that and the other question i'm worried about is the one where they had </p>
<p>I. 1 same zero
II. intersect at exactly 1 point
III. same range</p>
<p>i put II and III</p>
<p>^Haha yeah that's the third one I skipped because I didn't want to waste time on it.</p>
<p>and the one where it said "y is a function of x" it was only I right</p>
<p>gahhhhh</p>
<p>was it asking for which ones were RIGHT or WRONG?</p>
<p>cuz I was wrong, and II and III were right because you can only have 1 y value for every x value</p>
<p>but y is a function of x... so isnt it 1 y value for every x</p>