<p>for that one where it was like the inequality... 2x+5 < 12 3y+4 < 15 or something like that (don't really remember exactly...)</p>
<p>was it x+y<8?</p>
<p>Wait did it say which of these ALWAYS works? because i am pretty sure it didnt...
if not i put x < y</p>
<p>x+y<8 10ch</p>
<p>Just wondering though.. x < 4 and y < 13/3. How is that always x + y < 8 (i know its not what i put).</p>
<p>gyro i got that</p>
<p>uhhhhh.</p>
<p>i had the cube one and the parabola one, but no knots or precipitation...</p>
<p>and i had four math sections. three 25 and one short one.</p>
<p>did anyone get that logic question about "if i studied for my test, then i will pass" or something?</p>
<p>gyros. i wouldn't be specific about the question since I think some time zones still haven't finished the SATs (in fact I shouldn't be discussing answers at all but here it goes): add the inequalities together :)</p>
<p>but Y can be anything between 4 and 13/3 which would be greather than 8..</p>
<p>i thought it was 12/3
aka 4</p>
<p>Wow, I have been getting a lot of the questions that I was wondering about. Did anyone have one with 3 Circles that overlapped and you had to find the perimeter in the middle and the radius equaled like 10pi. I couldn't do it so I estimated the what fraction the perimeter of one of the circles was and got about 1/5. Then i calculated the circumference and divded by 5 and multiplied the answer by 3. Something like 35 or 36 I put.</p>
<p>it was 10pi</p>
<p>good because 10 pi is areound 35 36 which is what i put</p>
<p>No it said 3y + 4 < 17.. not 15
and it was 2x + 4 < 12.
oK ACH for the radius one think about it
it formed an equilateral triangle between all of those points.
Therefore the length of one arc was 1/6 the circumference then times by 3
so 2pi(10) / 6 * 3 = 10pi.</p>
<p>i also got x+y<8 i dont know why or how but that what i got</p>
<p>Thanks Gyros, I just wasn't think at all and really had to go to the bathroom. But since the value of 10pi was closest to my estimate, i got that one right</p>
<p>it didnt form a triangle
but it was 10pi so doesnt mattter how u got it</p>
<p>I agree with jjchase. if it was asking for the perimeter of an arch of a circle, how could there have been any straight lines? I think the equilateral triangle method would give you the exact fraction that the length of one of the segment's made up of the circle</p>
<p>No listen
draw the pic right now. Draw a triangle between the 3 points (the 3 raddi. all have 10). now next to yoru drawing, break up the circles. You should notice that its an equilateral triangle. I cant explain it well... but trust me. that was how you did it.</p>
<p>Worst case, 3 wrong 1 omit. Only think i got 2 wrong but thats why i said worst case. any score estimates??</p>
<p>it didnt have straight line
anyway we both got it right</p>