Official November 4 SAT Math Thread

<p>Did anybody have a shaded right triangle with an inscribed rectangle, where you had to find the area of the two triangles?</p>

<p>What was the question about the math sequence problem asking? The number of 3 digit numbers? I was confused because it didn't specify how many terms, and therefore it went on infinately...what did everyone get for answers?</p>

<p>Kristina: yes i had that, basically you just used pythagorean theorem to get the lengths of the triangle, then found the area of the BIG traingle. After that, subtract the area of the rectangle...</p>

<p>SParkshooter: the sequence of when one number was multiplied by two or something?...do it'd be like 1,2,4,8,16,32,64,128,256,512,1024...</p>

<p>so there would be 3, 3 digit numbers</p>

<p>answer for big triangle one was 21</p>

<p>area of big triangle = 30, subtracted by 9</p>

<p>did not have either of those questions</p>

<p>so can we compile the grid ins?
heres mine: 1
14
100
4.2
1350
5/4
12
70
8
4</p>

<p>pennywhistle, that question was 3. The numbers were 192, 384, and 768.</p>

<p>does anyone remember the one that say something like " there are 22 people going on a rollercoaster that can seat 2 adults or 3 kids in a seat, what's the max number of adults" something like that, i think i put 16 but if those numbers are right i think i got it wrong.</p>

<p>bannana girl I think I got 1050, not 1350. I think. Was it a triangle on top of a rectangle, and finding the area? Area of rect was 20x30=600, and area of triangle was 1/2 * 30 * 30 = 450. 600+450=1050</p>

<p>I thought it was 16 adults... Because they took up 10 seats, and 16 adults means 6 kids, so 8 cars for adults + 2 cars for kids = 10.</p>

<p>i remeber getting 1050 as well for that^ problem</p>

<p>Sweeet. :)</p>

<p>thats what i put, 16 adults, i just got the nubers mixed up when i was thinking of it after the test</p>

<p>I am not having any of these questions and by the look of it, my grid-ins must be all wrong</p>

<p>what about the one with a circle with radius r and it had the same area as the square it was inscribed in, i think i got r* the sqr root of pi. for the side length of the square.</p>

<p>1050 and 16 adults most definitely</p>

<p>was the one you gridded as 4, the x value for which f(x) is greater than k
b/c if so, i think it's incorrect</p>

<p>i got 0 because the y-int was greater than k</p>

<p>I also got 1050 and 16 adults.</p>

<p>yep
the x could have been from 0-->2 not including 2</p>