Official October 18, 2006 PSAT Discussion

<p>any1 know the answer/? of the math question with the square and a triangle ontop of it?</p>

<p>i totally forgot the >?</p>

<p>The side length of the square was 5, so area was 25. Add the triangle with area 6, and get 31. Was there another area to add though? I forget...</p>

<p>no
i think i got that but what were the sides of the triangle
was it 3x4 and if so, how do u get that
im almost 100 percent sure i wrote 31 though</p>

<p>what was that one in sentence completions, where it said--
because modern language is so explicate, -- is used less often
or it went something like that
did you guys put euphemisms? or garrulous? or i dont even remember the other answer choices</p>

<p>well garrulous means very wordy, which is an adjective, so garrulous wouldnt work, if the sentence you gave is accurate. Thanks, O' Reilly :)</p>

<p>two things:</p>

<p>1) sqrt(121)-3=8???
2) Roughly 0 wrong math. 2 wrong writing. 3 wrong critical reading. Score?</p>

<p>If the sides are 3 and 4, we can use the pythagoream theorem, because we knew it was a right-angled triangle:</p>

<p>a^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = c^2
25 = c^2
5 = c</p>

<p>So the side length of the square is 5, meaning its area is 25.
The triangle had legs of 3 and 4, so Area = b<em>h/2 = 3</em>4/2 = 12/2= 6.
25 + 6 = 31
Answer: 31</p>