<p>hi..</p>
<p>how did you guys do?</p>
<p>hi..</p>
<p>how did you guys do?</p>
<p>Hmm...first time taking it. I thought it was a bit difficult, I don't think I got a fantastic score or anything.</p>
<p>Ah well.</p>
<p>lol~</p>
<p>but how come it seems nobody took Chem today.</p>
<p>Yeah for some reason the chemistry discussions are kept to a minimal. I thought the test was reasonable plus minus some theory that wasn't covered in my AP Chem class. I was really excited to see that there were no problems on kinetics, I hate kinetics.</p>
<p>I thought chem was pretty hard compared to Barron's practice tests..</p>
<p>And it was harder than the Dec test.</p>
<p>I got up to Q65 or something.</p>
<p>Last time I got 620 with 0 prep - like actually 0 prep.
And I studied for a week this time and I was hoping to get like 690+ but I reckon I did worse than Dec.</p>
<p>My plan was to study everything except for Moles. I was so glad that there were hardly any questions on calculating mole stuff.</p>
<p>You mean you didn't study stoichiometry!? I don't know what the SAT II tests, but moles are pretty darn important ;)</p>
<p>Yeah. We covered them a bit in school (im not an AP chem student) but I was sooo confused and didn't understand anything.. took me like a month to understand what a mole was. And I only had a week of studying so I kinda tweezed that topic out of my plan.</p>
<p>What was the answer to the question ' Which of the following is the strongest Borwnsted Base? I only Remember 2 choices though: H2O and Cl-?</p>
<p>CO3 ^2-
and NH3</p>
<p>and OH-
lol~</p>
<p>I think its CO3^2-</p>
<p>i am not sure though.</p>
<p>The curve better be a little easy as compared to the one in the latest subject test book which only has a margin of 3 raw score. I thought the test was a lot harder than the one in that book.</p>
<p>I'm almost positive that hydroxide (OH-) is a stronger base than carbonate (CO3^2-). H2O is very weak and so is Cl- (since HCl is a strong acid and dissociates completely).</p>
<p>yeah, i know normally, OH-should be the stongest base, and thats also what i put at first, but because the question asks for the strongest Borwnsted base, which is defined as proton acceptor. And I think it implies that the one that accepts the largest number of protons should be the stoongest, and in case, the CO3^2-</p>
<p>lol~my 600th post.above~</p>
<p>Congratulations :) Maybe you're right--I have yet to sit myself down and really begin studying. Is acid strength measured based on *K*a value?</p>
<p>hi everyone...i just had a quick question, in case anyone on this chemistry thread is able to help:</p>
<p>What are the products of a reaction involving NaClO and Na2S2O3 in a basic environment? (I know it is a redox reacion in which the thiosulfate ion is oxidized to produce a sulfate ion, and the chloride ion is the reduction product of the hypochlorite ion.</p>
<p>Thanks!</p>
<p>can this reaction actaully occur?</p>
<p>acid strenght based on Ka value
yes~the stronger the acid, the more thoroughly it dissovles in water....</p>
<p>
[quote]
hi everyone...i just had a quick question, in case anyone on this chemistry thread is able to help:</p>
<p>What are the products of a reaction involving NaClO and Na2S2O3 in a basic environment? (I know it is a redox reacion in which the thiosulfate ion is oxidized to produce a sulfate ion, and the chloride ion is the reduction product of the hypochlorite ion.</p>
<p>Thanks!
[/quote]
I just did the redox reaction and this is the answer to your question:</p>
<p>S2O3(2-) + 4ClO- + 2OH- >>> 2SO4(2-) + H2O + 4Cl-</p>
<p>I was wondering how the SAT II Chem test compares to the AP Chem test.</p>
<p>I know my teacher teaches to the AP test, so I know everything on that.</p>
<p>Would I do well on the SAT II?</p>
<p>check the outline for the SAT chem test</p>
<p>and do some practive tests</p>
<p>you will do fine.</p>
<p>AP is MUCH more involved than SAT II. If you know AP Chem very well, you don't even need to study for the SAT II, you'll do very well on it. But do look at practice tests to familiarize yourself with the format.</p>