Official SAT Math IIc October Discussion

<p>I think we might be mixing up problems XD The other triangle had a 2 for one side. How did you get a 4/3?</p>

<p>ok then it was a 2/3 ratio, sorry i don't remember the other triangle</p>

<p>does anyone remember the letter choice for the factorial problem</p>

<p>Hmm... was it asking for what cosA was?
So, a 3-4-5 triangle versus a 2-?-? triangle... how does that equal 4/5? I'm slightly confused... I don't remember what I did anymore. Hahaha.</p>

<p>it was a 3-4-5 and a 1-2-rad3 triangle</p>

<p>Copy&Paste, it was something like (D)... I think...</p>

<p>factorial, umm D was it?</p>

<p>5! * 10!/5!</p>

<p>Wait... so if it was 1-2-rad3, how are the 2 triangle's angles similar? I don't remember them giving the sides for the smaller triangle.</p>

<p>you had to get cosA or something, so opposite over hypotenuse. 8/3 divided by 10/3</p>

<p>the angles were 30 60 90. i think i twas asking the ratio of the big triangle so 4/5</p>

<p>Wait are you guys talking about the similar triangle problem that was in the beginning like #12. Becuse its was the Cos A, but the means adjacent/hpt, not opposite/hpt.</p>

<p>anyone remember any more?</p>

<p>for the 2 circles or 4 pts, i still think its 4 pts.
think of it this way: 1
1
-------------------- 1------------->
1
1
perp. line and plane. all points 5 units from plane = 2 planes right?
all points 4 units from the line = 2 parallel lines only,not circles, because distance means perpendicular distance, so only a parallel line can have perp. distance 4 to another line. a circle's center to the outside of the circle creates angles other than 90, which is not the def. of distance.
So 2 parallel lines intersect with 2 planes at 4 pts. correct?</p>

<p>heyyy do you guys remember the ANSWER CHOICE FOR 48 - 50?
i just remember the letters. i got DDA
is that right??
man todays test was easier than all the practice ones i've taken but i made soo many stupid mistakes =&lt;/p>

<p>It was asking for cosA, A being the angle from which 2 is the adjacent. I thought it wanted to know 2/hypotenuse = cosA?</p>

<p>oops it should look like this
1
1--------->
1
1</p>

<p>Yeah, I made stupid mistakes probably. </p>

<p>I still think it's a circle because you have to include all the POSSIBLE points. Lines are not inclusive.</p>

<p>Yes it asked for cosA which one the big triangle was 3/5 and on the small triangle was 2/ (5 * (2/3), which is the ratio. Either way you get 3/5, because similar tiangles have the same angles</p>

<p>how could it be a circle, if the center of the circle is on the perpendicular line, then each radius out towards the 2 planes that are 5 units from the intersected plane will not be at a perpendicular angle. therefore each radius cannot count as being both 4 units from the circle, and 5 from the plane. </p>

<p>4 are the only possible pts.</p>

<p>yeahh i got two circles too
is that correct?
hope so</p>

<p>Yeah, I got 3/5... Am I wrong? AGAIN? AAH! sky2345, you're sure it's 3/5?</p>

<p>It was 2 circles because I remember plotting -+4 and -+5 for the outermost points. Connect = Circle, which includes all the innermost points also.</p>